Answer:
Solution given:
AD=1.8
AC=3.0
we have
∆ADC is a right angled triangle
Cos A=b/h
<A=cos-¹ (1.8/3)
<A=53.13°
again
∆ABC is a right angled triangle
Tan A=p/b=BC/AC
Tan 53.13×3=BC
BC=4
NOW
Area of triangle =½(AC*BC)=½(4×3)=6 <u>square </u><u>units</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>area</u><u>.</u>
X - y/2 = 4
x - 4 = y/2
2(x - 4) = y
2x - 8 = y.....so we sub in 2x - 8 in for y in the other equation
3x - 2y = 11
3x - 2(2x - 8) = 11
3x - 4x + 16 = 11
-x = 11 - 16
-x = -5
x = 5
2x - 8 = y
2(5) - 8 = y
10 - 8 = y
2 = y
It has one solution and it is (5,2)
Answer:
1
Step-by-step explanation:
Slope intercept form is: y=mx+b
b is your y-intercept
Answer:
Step-by-step explanation:
total = 1 + 2 + 4 + 3 = 10
blue then blue = 2/10 * 2/10 = 1/5 * 1/5 = 1/25
green then red = 4/10 * 3/10 = 12/100 = 3/25