Use the model to solve for x.

Mathematics

2 answers:

pav-90 [236]4 years ago

7 0

A) X= 1 is the correct answer, hope this helps :)

kenny6666 [7]4 years ago

7 0

A is the correct answer

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A certain plant runs three shifts per day. Of all the items produced by the plant, 50% of them are produced on the first shift,

Snezhnost [94]

Answer:

0.2941 = 29.41% probability that it was manufactured during the first shift.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Defective

Event B: Manufactured during the first shift.

Probability of a defective item:

1% of 50%(first shift)

2% of 30%(second shift)

3% of 20%(third shift).

$P(A) = 0.01*0.5 + 0.02*0.3 + 0.03*0.2 = 0.017$

Probability of a defective item being produced on the first shift:

1% of 50%. So

$P(A \cap B) = 0.01*0.5 = 0.005$

What is the probability that it was manufactured during the first shift?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.005}{0.017} = 0.2941$

0.2941 = 29.41% probability that it was manufactured during the first shift.

6 0

3 years ago

About 6% of the population has a particular genetic mutation. 600 people are randomly selected. find the standard deviation for

Rina8888 [55]

Assume a binomial distribution. Then the mean of the distribution is $np$ , where $n$ is the number of people taken in a sample and $p$ is the probability of the mutation occurring in any given person, and the standard deviation is $\sqrt{np(1-p)}$ . Then in this case, the standard deviation is $\sqrt{600(0.06)(0.94)}\approx5.82$ .