The slope-intercept form of the given equation ( 8x 10y=-30 ) is y = (-4/5)x - 3.
<h3>What is the slope-intercept form of the given equation?</h3>
The slope-intercept form is expressed as;
y = mx + b
Where m is the slope and b is the y-intercept.
Given the equation in the question;
8x + 10y = -30
To convert to slope intercept form, we make y the subject of the formula and simplify.
8x + 10y = -30
10y = -8x - 30
Divide each term by 10
10y/10 = -8x/10 - 30/10
y = -4x/5 - 3
y = (-4/5)x - 3
Therefore, the slope-intercept form of the given equation ( 8x 10y=-30 ) is y = (-4/5)x - 3.
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Well it's 70+42+70+48 or 230 sq. ft
Nickels is 0,05 of dolar - n
dimes is 0,1 o dolar -d
quarters is 0,25 of dolar -q
dimes =2nickels
d=2n
quarters=2dimes
q=2d=4n
12,5=n(0,05)+2n(0,1)+4n(0,25)
12,5=0,05n+0,2n+n
12,5=1,25n
n=10
q=4n=40
There are 40 quarters
Answer:
1. From sin²θ +cos²θ =1 and sinθ=-2/3, we see that cosθ=√(1-sin²θ) or cosθ=√5/3, where the sign of cosine is positive as it is in Quadrant IV. x lies in 4th quadrant , cos x is +ve. , cos x = √5/3. Answer.
answer : cos x = √5/3
2. 4/3
3. sin (- theta) = - sin (x) so sin x = 1/6
tan = sin / cos = 1/6 / cos = - sqrt35/35 solve for cos
cos = 1/6 * (-35/sqrt35)
= -35 sqrt35 /210
answer : −35/√210
4. The cosine function is an even function, so cos(θ) = cos(-θ).
The relationship between sin(θ) and cos(θ) is sin(θ) = ±√(1 -cos(θ)^2)
For sin(θ) < 0 and cos(θ) = (√3)/4, sin(θ) = -√(1 -3/16) = -√(13/16)
sin(θ) = -(√13)/4 For sin(θ) < 0 and cos(0) = √(3/4), ...
sin(θ) = -√(1 -3/4) = -√(1/4) sin(θ) = -1/2
answer : -13/√4
5. answer : tan^2 θ ⋅ cos^2 θ = 1 − cos^2 θ would be the first step
