Answer: pituitary gland
Explanation: In an oophorectomy procedure as both ovaries were removed due to which hypothalamus, pituitary and ovarian axis mainly damaged. When ovaries removed than LH (luteinizing hormone) and FSH ( follicle stimulating hormone) level increased by the pituitary gland. The hormones that are produced by ovaries also decrease in which estrogen and progesterone level decreased which cause list of problems in females.
Answer:
Answer is C. Damage to C3, C4 or C5.
Explanation:
C1 - C7 are used to represent the number of vertebrae found at the cervical region of the vertebrae canal or column. The vertebrae column comprises off various vertebrae that protect the spinal cord,which starts from the neck region to the tail region.
The C3, C4 and C5 are at the midsection of the cervical region of the spine , and they provide support for the neck and the head.
These vertebrae contain nerves which if affected will cause a serious pain. which can actually affect his breathing. Because, the spinal nerves around the spinal cord are linked to the brain.
The phenotype of antenna in crawfish depends on the protein amount in the antenna length. The offspring have different phenotype than their parent because of the amount of protein translated from each parent gene is determining in this.
The gene determines the amount of protein to be present in the antenna to determine its length.
Explanation:
Data given:
Two crawfish parent = medium length antennae, genotyoe Ll
One offspring = short antenna, genotype ll
one offspring = long antennae, genotype LL
The traits in offspring is shown as:
L l
L LL Ll
l Ll ll
The proportion of allele present in the gene determined the length of the antenna in crawfish.
The difference in length of the antenna in crawfish is due to the amount of protein for the phenotype present in the individual. The amount of protein to be expressed in the crawfish is given by both the parents. The tendency of protein expresed define the phenotype of antenna length.
The phosphorylation of fructose 6-phosphate to fructose-1,6-bisphosphate is the committed step in glycolysis because<u> fructose 1,6-bisphosphate can undergo no other reactions than those of glycolysis.</u>
<h3>
What is phosphorylation?</h3>
- The crucial process of glycolysis involves the breakdown of glucose into two molecules of pyruvate. It involves a number of steps and many enzymes.
- It takes place over the course of ten phases, demonstrating how important and crucial phosphorylation is to the production of the final goods. Step 1 of the preliminary step (first half of glycolysis) and step 6 of the payout phase reactions are started by phosphorylation (second phase of glycolysis).
- Because fructose-6-phosphate cannot cross the cell membrane, it is forced to remain inside the cell. Step 3 involves phosphorylation, when fructose-6-phosphate is changed into fructose-1,6-bisphosphate.
To learn more about phosphorylation with the given link
brainly.com/question/15585148
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<span>c. co2 and h2o are converted to carbohydrates
Hope this helps!</span>
