Well, currently in our revolving world, computers are mostly used which led to laziness for some people. However the school systems in most countries still depend on manual computing which can be really essential to the current generation. Computing can really change our current world, it helps us to not depend on computers, gives people more job opportunities. Helps to strengthen brain power which can contribute to large variety of factors. A smarter generation, and if possible, a more advance society.
Answer:
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE)
Explanation:
JFrame is the swing class that is used to display a frame object. The JFrame display contains an X button on the top right position which is used to turn off the display of the frame. However if we want to terminate the program on pressing the X button, we need to update the DefaultCloseOperation for the frame. JFrame provides a method ''setDefaultCloseOperation' for this purpose. When this method is called with the argument JFrame.EXIT_ON_CLOSE , it will cause the program to exit when the close button is pressed.
Answer:
It promotes self-expression
It holds the government accountable
It keeps us informed
Explanation:
I got them right Ed
Answer:
It can be repaired with disk utility / recovery algorithms
In UNIX it can be done by scanning
In FAT file scan the FAT looking for free entries
Explanation:
When the crash happens, it is not a problem for UNIX and FAT file system
It can be repaired with disk utility/recovery algorithms.
The recovery algorithm is a list of all blocks in all files and takes a compliment as new free file.
In UNIX scanning can be done at all I-nodes.
In FAT file problem cannot occur because there is no free list .If there was any problem than it would have to be done to recover it to scan the FAT looking for free entries.
Answer:
Starting from root, recursively traverse the min-heap. Once we find a key with value less than our X, we know that every key in subtree of that key will be also smaller than our X. Otherwise, we should keep traversing.
Explanation:
The complexity of this algorithm will be O(N) where N is the number of keys in our min-heap.
