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tatyana61 [14]
3 years ago
10

An outfielder throws a baseball to the player on third base. The height h of the ball in feet is modeled by the function h(t) =

-16t2 + 19t + 5, where t is time in seconds. A player on the opposing team starts running from second base to third base 1.2 s before the outfielder throws the ball. The distance between the bases is 90 ft, and the runner's average speed is 27 ft/s. Will the runner reach third base before the ball does?
Mathematics
1 answer:
slava [35]3 years ago
8 0
No he will not very close though

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A year has 365 days, and a day has 24 hours. If an hour has 60 minutes and a minute has 60 seconds, how many seconds are there i
motikmotik
Ok, so we need to take 60 x 60.  That gives us 3600, which is the amount of seconds in 60 minutes.  Then we need to take 3600 x 24, to figure out the number of seconds in 24 hours (1 full day).  That gives us 86,400.  Finally, we take 86400 x 365, to determine how many seconds are in 1 full year (365 days).  That gives us the answer of <span>31536000.  Hope this helps!</span>
7 0
3 years ago
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The sum of two consecutive integers is 201 find the integers
telo118 [61]

100 and 101

the two integers are n and n+1. this means that 2n+1=201. n=100 and n+1=101

8 0
3 years ago
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If r=10 and s=31 find R. Round to the nearest tenth
Vsevolod [243]

Answer: option c.

Step-by-step explanation:

You need to remember the identity:

tan\alpha=\frac{opposite}{adjacent}

The inverse of the tangent function is arctangent. You need to use this to calculate the angle "R":

 \alpha =arctan(\frac{opposite}{adjacent})

You know that you need to find the measure of "R" and r=10 (which is the opposite side) and s=31 (which is the adjacent side), you can sustitute values into \alpha =arctan(\frac{opposite}{adjacent})

Then, you get:

R=arctan(\frac{10}{31})\\\\R=17.9\°

3 0
4 years ago
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WILL GIVE BRAINLIEST AND 30 POINTS<br><br> What are 2 expressions that are equivalent to 5(2j+3+j)
VMariaS [17]
5(2j+3+j)
= 5(2j) + 5(3) + 5(j) we distribute 5 to all of the expression
= 10j + 15 + 5j connect like terms j
= 15j + 15
6 0
3 years ago
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Gretchen has a set of blocks of heights 1, 2, and 4-centimeters. Imagine stacking the blocks one on top of the other to make a t
notsponge [240]

Answer:

t_{n}=t_{n-1}+t_{n-2} +t_{n-4}

Step-by-step explanation:

t_{n}=multiple ways to climb a tower

When n = 1,

tower= 1 cm  

t_{1}= 1

When n = 2,

tower =2 cm   

t_{2}= 2

When n = 3,

tower = 3 cm

it can be build if we use three 1 cm blocks

t_{3} = 3

When n = 4,

tower= 4 cm

it can be build if we use four 1 cm blocks

t_{4} = 6

When n > 5

tower height > 4 cm

so we can use 1 cm, 2 cm and 4 cm blocks

so in that case if our last move is 1 cm block then t_{n-1} will be

n —1 cm

if our last move is 2 cm block then t_{n-2} will be

n —2 cm

if our last move is 4 cm block then t_{n-4} will be

n —4 cm

 

t_{n}=t_{n-1}+t_{n-2} +t_{n-4}

4 0
4 years ago
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