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aniked [119]
3 years ago
6

Micky spent 3 1/4 hours practicing his trumpet. He needs to spend 5 1/2 hours receive an A in band. How many hours does Mickey n

eed to spend practicing his trumpet?
no need for steps
Mathematics
1 answer:
astra-53 [7]3 years ago
8 0

5 1/2 - 3 1/4

5 2/4 - 3 1/4

2 1/4 hours are still required

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KatRina [158]
9 x 9 = 81
81 - 21 = 60
60 / -6
10
4 0
3 years ago
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I don't understand the substitution method?
liq [111]
It depends on what variable you are tying to solve for first. Say you are trying to solve for x first and then y on the first problem you wrote.

In substitution you solve one of the equations for example with
6x+2y=-10
2x+2y=-10
you solve 2x+2y=-10 for x

2x+2y=-10
-2y = -2y (what you do to one side of the = you do to the other)
2x=-10-2y (to get the variable by its self you divide the # and the variable)
/2=/2 (-10/2=-5 and -2y/2= -y or -1y, they are the same either way)
x=-5-y

now you put that in your original equation that you didn't solve for:
6(-5-y)+2y=-10 solve for that
-30-6y+2y=-10 combine like terms
-30-4y=-10 get the y alone and to do this you first get the -30 away from it
+30=+30
-4y=20 divide the -4 from each side
/-4=/-4 (20/-4=-5)
y=-5

now the equation you previously solved for x can be solved for y.
x=-5-y
x=-5-(-5) a minus parenthesis negative -(- gives you a positive
-5+5=0
x=0

and now we have solved the problem. x=0 and y=-5

6 0
3 years ago
IMPORTANT PLEASE I NEED NOW:Find the area of each face of the cube whose volume is 729 cm
vivado [14]

Answer:

81

Step-by-step explanation:

square root of 729= 9

9×9=81

8 0
3 years ago
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A triangle has the coordinates
kotegsom [21]

Answer:

Go on Mathify! It’s a free website that could help you with ur math homework and it’s a chat

Step-by-step explanation:

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3 years ago
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Solve for x. (e^x-e^-x)/((e^x+e^-x)=t
Sergio [31]
\dfrac{e^x-e^{-x}}{e^x+e^{-x}}=t\\\\
\dfrac{e^{2x}-1}{e^{2x}+1}=t\\\\
e^{2x}-1=t(e^{2x}+1)\\\\
e^{2x}-1=e^{2x}t+t\\\\
e^{2x}-e^{2x}t=t+1\\\\
e^{2x}(1-t)=t+1\\\\
e^{2x}=\dfrac{t+1}{1-t}\\\\
e^{2x}=-\dfrac{t+1}{t-1}\\\\
2x=\ln\left(-\dfrac{t+1}{t-1}\right)\\\\
x=\dfrac{\ln\left(-\dfrac{t+1}{t-1}\right)}{2}\qquad t\in(-1,1)




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