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UNO [17]
3 years ago
15

Eating disorders are managed by using which of the following techniques?

Mathematics
2 answers:
rodikova [14]3 years ago
7 0

Answer:

What are the option choices?

Step-by-step explanation:


Ghella [55]3 years ago
3 0
The sun need to be more brighter
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Write the formula for the area of a triangle, A=1/2bh in terms of h. Find the height of a triangle when A = 18 in. squared and b
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The height of the given triangle is  

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There are 60 tables in a restaurant, with 25% of them seating 2 people.
Ratling [72]
Hello! So, 25% of the 60 tables seat two people. To find this number, multiply 60 by 25%. 60 * 25% (0.25) is 15. 15 of them seat 2 people and 15 * 2 is 30.The other 45 tables seat 4 people. When you multiply both number, you get 180. Now, let's add the numbers together. 180 + 30 is 210. There are 210 seats in the restaurant. The answer is C: 210.
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Find the inner product for (7,1) (0 -2) and state whether the vectors are perpendicular.
Fofino [41]

Answer:

the answer is 67.980

Step-by-step explanation:

6 0
3 years ago
Suppose a batch of metal shafts produced in a manufacturing company have a standard deviation of 1.5 and a mean diameter of 205
Crank

Answer:

P(205-0.3=204.7

z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778

z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778

So we can find this probability:

P(-1.778

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

P = 1-0.9243 = 0.0757

Step-by-step explanation:

Let X the random variable that represent the diamters of interest for this case, and for this case we know the following info

Where \mu=205 and \sigma=1.5

We can begin finding this probability this probability

P(205-0.3=204.7

For this case they select a sample of n=79>30, so then we have enough evidence to use the central limit theorem and the distirbution for the sample mean can be approximated with:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}

And we can find the z scores for each limit and we got:

z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778

z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778

So we can find this probability:

P(-1.778

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

P = 1-0.9243 = 0.0757

6 0
3 years ago
Help me please<br> Find the value of x.
Otrada [13]

Answer:

110

Step-by-step explanation:

180-35-35

8 0
3 years ago
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