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2 years ago

Write as a fraction and simplify. (use the symbol / in your answer). 0.878787.....

Mathematics

1 answer:

Alika [10]2 years ago

3 0

Answer:

.878787.. to a fraction is 29/33

Step-by-step explanation:

$\frac{(0.87*100)-0}{99}$ = 87/99

Simplify 87/99, which is 29/33

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1 1/4 as a improper fraction

ludmilkaskok [199]

That would be
5/4
.
Explanation:
This answer is valid because, when you multiply
4
×
1
, you get
4
. Then add one and keep the denominator, you will get
5
4
.
1
1
4
=
1
×
4
+
1
4
=
5
4
When you simplify
5
4
, you will get
1
1
4
Have a great day!

8 0

3 years ago

Read 2 more answers

Jaz was 43 inches tall. Eighteen months later, she was 52 inches tall. The constant rate of change for Jaz's height was .

maxonik [38]

Answer:

Constant rate of change for Jaz height will be 0.5 inch per month

Step-by-step explanation:

Jaz present height is 43 inches.

Eighteen months later her height will be 52 inches.

Now we know rate of change will be represented by the formula

Rate of change of height =

= 0.5 inch per month

The constant rate of change for Jaz height will be 0.5 inch per month.

Read more on Brainly.com - brainly.com/question/2012372#readmore

7 0

3 years ago

At the beginning of the month, Sheryl had a balance of $120 in her checking account. She then made a purchase for $80, using her

kolezko [41]

Answer:

$80

Step-by-step explanation:

4 0

3 years ago

A researcher claims that the variation in the salaries of elementary school teachers is greater than the variation in the salari

guajiro [1.7K]

Answer:

The null hypothesis is $H_o : \sigma^2_1 = \sigma^2 _2$

The alternative hypothesis is $H_a : \sigma_1 ^2 > \sigma^2_2$

$F_{critical} = 1.8608$

$F = 2.9085$

The decision rule is

Reject the null hypothesis

There is sufficient evidence to support the researchers claim

Step-by-step explanation:

From the question we are told that

The first sample size is $n_1 = 30$

The sample variance for elementary school is $s^2_1 = 8324$

The second sample size is $n_2 = 30$

The sample variance for the secondary school is $s^2_2 = 2862$

The significance level is $\alpha = 0.05$

The null hypothesis is $H_o : \sigma^2_1 = \sigma^2 _2$

The alternative hypothesis is $H_a : \sigma_1 ^2 > \sigma^2_2$

Generally from the F statistics table the critical value of $\alpha = 0.05$ at first and second degree of freedom $df_1 = n_1 - 1 = 30 - 1 = 29$ and $df_2 = n_2 - 1 = 30 - 1 = 29$ is