Answer:
<h2>13x - 1. Term</h2><h2>5y - 1. Term</h2><h2>13 - 3. Coefficient</h2><h2>2 - 2. Constant</h2><h2>5 - 3. Coefficient</h2><h2>y - 4. Variable</h2><h2>3 - 2. Constant</h2><h2>x - 4. Variable</h2>
Step-by-step explanation:
<h3>13x + 5y - 2 = 3</h3><h3 /><h3><u>Term</u> has a <em>number and also a variable</em>. </h3><h3>Ex.: 5y</h3><h3 /><h3><u>Constant</u> is any <em>number without a variable</em>.</h3><h3>Ex.: 3</h3><h3 /><h3><u>Coefficient</u> is the <em>number in a term</em>.</h3><h3>Ex.: 13</h3><h3 /><h3><u>Variable</u> is any <em>letter</em> in the equation.</h3><h3>Ex.: x</h3><h3 />
Answer:
Ntoine and Tess have a disagreement over how to compute a 15% gratuity on $46.00.
This in real becomes :
dollars
But, Tess says, "It is easy to find 10% of 46 by moving the decimal point one place to the left to get $4.60. Do that twice. Then add the two amounts to get $4.60 + $4.60 = $9.20
So, Tess is wrong. Rather she should have done 10% of $46 giving $4.6 and then half of 4.6 that is 2.3 dollars. Getting a total of dollars which is the real amount.
Answer:
Katie won't have more than 100 seashells until the 6th day.
Step-by-step explanation:
No. of seashells to be collected = 100
Initial number of seashells in the collection = 34
No, of seashells found each day = 12
So, number of seashells collected in d days = 12·d
Total number of seashells collected after d days = 34 + 12·d
Number of days needed by Katie to save more than 100 seashells :
34 + 12·d > 100
Subtracting 34 from both the sides
⇒ 12·d > 66
⇒ d > 5.5
Hence, Katie won't have more than 100 seashells until the 6th day.
What you can do in this case is the following rule of three to find the result:
1 light year ---> 5.88 * 10 ^ 12 miles
3.2 * 10 ^ 2 light year ---> x
Clearing x we have:
x = ((3.2 * 10 ^ 2) / (1)) * (5.88 * 10 ^ 12)
x = 1.88 * 10 ^ 15 miles
answer:
In scientific notation, approximately it is 1.88 * 10 ^ 15 miles