Answer: The length of rectangle is 15 cm and width is 20 cm
Step-by-step explanation:
As according to question
Let the width of rectangle = x cm
Length of rectangle =(x- 5) cm
Area of rectangle is 300 cm²
As we know Area of rectangle is given by
![Area = length \times breadth \\\\\Rightarrow 300 = (x-5)x\\\\\Rightarrow 300 = x^2-5x\\\\\Rightarrow x^2-5x-300 = 0 \\\\\Rightarrow x^2-20x+15x-300 = 0 \\\\\Rightarrow x(x-20) +15(x-20) =0\\\\\Rightarrow (x-20)(x+15)=0](https://tex.z-dn.net/?f=Area%20%3D%20length%20%5Ctimes%20breadth%20%5C%5C%5C%5C%5CRightarrow%20300%20%3D%20%28x-5%29x%5C%5C%5C%5C%5CRightarrow%20300%20%3D%20x%5E2-5x%5C%5C%5C%5C%5CRightarrow%20x%5E2-5x-300%20%3D%200%20%5C%5C%5C%5C%5CRightarrow%20x%5E2-20x%2B15x-300%20%3D%200%20%5C%5C%5C%5C%5CRightarrow%20x%28x-20%29%20%2B15%28x-20%29%20%3D0%5C%5C%5C%5C%5CRightarrow%20%28x-20%29%28x%2B15%29%3D0)
Therefore either (x-20)= 0 or (x+15)=0
i.e. either x= 20 or x = -15
Now width can not be negative
Therefore it cant be -15
Hence the width is 20 cm
Length = x- 5 = 20-5 = 15 cm
Hence the length of rectangle is 15 cm and width is 20 cm