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s344n2d4d5 [400]
3 years ago
10

Can Someone Help me​

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
8 0

Answer:

The super dark one is 12/24 or 1/2

and the lighter grayish one is 8/12

so 12/24 x 8/12

Hope this helped! PLease mark as brainliest! THanks!!!

Step-by-step explanation:

You might be interested in
Christian created a model
larisa86 [58]

Answer:

7 inches

Step-by-step explanation:

250.4/36= 6.955555 rounded to nearest inch is 7

5 0
3 years ago
In arithmetic sequence the first term is 5 and the common difference is 4. Determine the 6th term of sequence
Harlamova29_29 [7]

Answer:

The 6th term of the sequence is 25

Step-by-step explanation:

first term = a = 5

common difference = d = 4

The nth term of a sequence is

T_n = a + (n - 1)d

Therefore, the 6th term of the sequence is

T_6 = a + (6 - 1)d

T_6 = a + 5d

T_6 = 5 + 5(4)

T_6 = 5 + 20

T_6 = 25

3 0
3 years ago
Part A: Describe how you can decompose this shape into triangles. (2 points)
kvv77 [185]

Answer:

A: 6 triangles with height 10.4 inches each and base 12 inche

B: 62.4 square inches

C: 374.4 square inches

Step-by-step explanation:

Part A: You can form a triangle by connecting E to the top of the segment and connecting the top of the segment to D. Recreating this with each section will create 6 triangles with height 10.4 inches each and base 12 inches.

Part B: The area of a triangle is A = 1/2b*h. Substitute h = 10.4 and b = 12.

A = 1/2*10.4*12 = 62.4

Part C: There are 6 triangles each with area 62.4. So the area of the whole figure will be 6*62.4 = 374.4.

8 0
3 years ago
A coin is tossed 5 times. Find the probability that all are heads. Find the probability that at most 2 are heads.
fenix001 [56]

Answer:

1/32

15/32

Step-by-step explanation:

For a fair sided coin,

Probability of heads, P(H) = 1/2

Probability of tails P(T)  = 1/2

For a coin tossed 5 times,

P( All heads)

= P(HHHHH),

= P (H) x P(H) x P(H) x P(H) x P(H)

= (1/2) x (1/2) x (1/2) x (1/2) x (1/2)

= 1/32 (Ans)

For part B, it is easier to just list the possible outcomes for

"at most 2 heads" aka "could be 1 head" or "could be 2 heads"

"One Head" Outcomes:

P(HTTTT), P(THTTT) P(TTHTT), P(TTTHT), P(TTTTH)

"2 Heads" Outcomes:

P(HHTTT), P(HTHTT), P(HTTHT), P(HTTTH), P(THHTT), P(THTHT), P(THTTH), P(TTHHT), P(TTHTH), P(TTTHH)

If we count all the possible outcomes, we get 15 possible outcomes representing "at most 2 heads)

we know that each outcome has a probability of 1/32

hence 15 outcomes for "at most 2 heads" have a probability of

(1/32) x 15  = 15/32

8 0
3 years ago
Read 2 more answers
The midpoint of AB is M(3,3). If the coordinates of A are (2,-8), what are the coordinates of B?
Lyrx [107]

Step-by-step explanation:

MID POINT =[(X1 +X2)/2 , (Y1 +Y2)/2]

WE KNKW THAT A(2,–8) AND THE MID POINT IS (3,3)

SUBSTITUTING INTO THE EQUATION ABOVE

(3,3) = [(2+ X2)/2 ,(–8+ Y2)/2]

EQUATING THE X COORDINATES

=> 3 = (2+ X2)/2 (CROSS MULTIPLY)

=> 6 = 2 + X2

X(subscript 2)= 4

EQUATING THE Y COORDINATES

=> 3 =(–8 +Y2)/2 (CROSS MULTIPLY)

6 = –8 +Y2

=> Y(subscript 2)= 14

THEREFORE THE COORDINATES OF B ARE (4 ,14)

hope this helps :)

4 0
3 years ago
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