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lord [1]
3 years ago
15

5x-4y=-18 what is the three point on a graph for this equation

Mathematics
1 answer:
Tju [1.3M]3 years ago
5 0
(1)Draw the "y" line . It goes up and down. 
<span>Make sure to mark the centimeters or quarter inches with little nobs. </span>
<span>Start at -20 and go to 10 </span>
<span>(2)Draw the "x" line. it goes side to side. </span>
<span>place the x line at the zero point of the y line. I'm sure you will see your paper looks like the letter "t". Perfectly at a right angle. you could use the corner of a book to square it. </span>

<span>Now for the maths 5x - 4y = -18. The most important symbol here is the "=" sign. </span>
<span>(3) rearrange the equation so that y is on one side of "=" and x is on the other side. </span>
<span>Remember if you add 10 to one side the of "=" , then for it to be equal, add 10 to the other. side also </span>
<span>so add 4y to both sides. add 18 to both sides . divide the whole of each side by 4. </span>
<span>5x - 4y + 4y + 18 = -18 + 4y + 18 </span>
<span>1.25x + 4.5 = y </span>
<span>(4) now write down on a peace of scrap paper, x=1, y= 5.75, x=2 y= ___ , x=3 y= ___ </span>
<span>(5) remember BEDMAS, and put 1 in the place of x and calculate what y is . </span>
<span>(6) get your ruler , line up x = 1 (ruler is going up and down) and draw a spot on what y = . Get two rulers if you must. </span>
<span>(7) </span>
<span>hey presto, you got your three points on a graph.</span>
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For the level 3 course, exam hours cost twice as much as workshop hours, workshop hours cost twice as much as lecture hours. How
natulia [17]
<h2>Answer</h2>

Cost of lectures = $7.33 per hour

<h2>Explanation</h2>

Let e the cost of the exam hours

Let w be the cost of the workshop hours

Let l be the cost of the lecture hours.

We know from our problem that exam hours cost twice as much as workshop, so:

e=2w equation (1)

We also know that workshop hours cost twice as much as lecture hours, so:

w=2l equation (2)

Finally, we also know that 3hr exams 24hr workshops  and 12hr lectures cost $528, so:

3e+24w+12l=528 equation (1)

Now, lets find the value of l:

Step 1.  Solve for l in equation (3)

3e+24w+12l=528

12l=528-3e-24w equation (4)

Step 2. Replace equation (1) in equation (4) and simplify

12l=528-3e-24w

12l=528-3(2w)-24w

12l=528-6w-24w

12l=528-30w equation (5)

Step 3. Replace equation (2) in equation (5) and solve for l

12l=528-30w

12l=528-30(2l)

12l=528-60l

72l=528

l=\frac{528}{72}

l=\frac{22}{3}

l=7.33

Cost of lectures  = $7.33 per hour



3 0
3 years ago
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Line e is a segment bisector of AB at point M. If AM = 4n-40 &amp; MB = 7(-2n+2), find the value of n.​
Mrac [35]

Answer:

the answer orange is n=3

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2 years ago
Divide (x^2+9x+19)÷(x+5)
gayaneshka [121]
Since this can’t be factored easily, you have to use synthetic division. This makes the answer x+4+(-1/x+5)

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Natalija [7]

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3 0
3 years ago
Evaluate the expression below using the properties of operations. Show your steps.−36 ÷ 14 ⋅ (−18) ⋅ (−3) ÷ 6
s2008m [1.1K]

Answer:

(-162)/7 or -23 1/7 as mixed fraction

Step-by-step explanation:

Simplify the following:

(-36)/14 (-18) (-3)/6

Hint: | Express (-36)/14 (-18) (-3)/6 as a single fraction.

(-36)/14 (-18) (-3)/6 = (-36 (-18) (-3))/(14×6):

(-36 (-18) (-3))/(14×6)

Hint: | In (-36 (-18) (-3))/(14×6), divide -18 in the numerator by 6 in the denominator.

(-18)/6 = (6 (-3))/6 = -3:

(-36-3 (-3))/14

Hint: | In (-36 (-3) (-3))/14, the numbers -36 in the numerator and 14 in the denominator have gcd greater than one.

The gcd of -36 and 14 is 2, so (-36 (-3) (-3))/14 = ((2 (-18)) (-3) (-3))/(2×7) = 2/2×(-18 (-3) (-3))/7 = (-18 (-3) (-3))/7:

(-18 (-3) (-3))/7

Hint: | Multiply -18 and -3 together.

-18 (-3) = 54:

(54 (-3))/7

Hint: | Multiply 54 and -3 together.

54 (-3) = -162:

Answer:  (-162)/7

3 0
3 years ago
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