Let the positive odd numbers be x,x+2,x+4.
According to the question,
5(3x+30)=72+x^2+4x
x^2-13x+42=0
(x-6) and (x-7)=0
x=6 or x=7
Answer:
3x +2x-5+(-7x+8)=
-2x+3
Step-by-step explanation:
Answer:
36π
Step-by-step explanation:
The area of a circle is given as:
![A = \pi r^2](https://tex.z-dn.net/?f=A%20%3D%20%5Cpi%20r%5E2)
where r = radius of the circle
The area of a sector of a circle is given as:
![A_s = \frac{\alpha }{2\pi} * \pi r^2](https://tex.z-dn.net/?f=A_s%20%3D%20%5Cfrac%7B%5Calpha%20%7D%7B2%5Cpi%7D%20%2A%20%5Cpi%20r%5E2)
where α = central angle in radians
Since
is the area of a circle, A, this implies that:
![A_s = \frac{\alpha }{360} * A](https://tex.z-dn.net/?f=A_s%20%3D%20%5Cfrac%7B%5Calpha%20%7D%7B360%7D%20%20%2A%20A)
A circle has a sector with area 33 pi and a central angle of 11/6 pi radians.
Therefore, the area of the circle, A, is:
![33 \pi = \frac{\frac{11 \pi}{6} }{2 \pi} * A\\\\33\pi = \frac{11}{12} * A\\\\=> A = \frac{33\pi * 12}{11}\\ \\A = \frac{396 \pi}{11} \\\\A = 36\pi](https://tex.z-dn.net/?f=33%20%5Cpi%20%3D%20%5Cfrac%7B%5Cfrac%7B11%20%5Cpi%7D%7B6%7D%20%7D%7B2%20%5Cpi%7D%20%2A%20A%5C%5C%5C%5C33%5Cpi%20%3D%20%5Cfrac%7B11%7D%7B12%7D%20%2A%20A%5C%5C%5C%5C%3D%3E%20A%20%3D%20%5Cfrac%7B33%5Cpi%20%2A%2012%7D%7B11%7D%5C%5C%20%5C%5CA%20%3D%20%5Cfrac%7B396%20%5Cpi%7D%7B11%7D%20%5C%5C%5C%5CA%20%3D%2036%5Cpi)
The area of the circle is 36π.