If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.
Given that m∠ABF=41° and BF is an angle bisector.
We are required to find the angle m∠BCE if BF is an angle bisector.
Angle bisector basically divides an angle into two parts.
If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.
In this way ∠ABC=2*∠ABF
∠ABC=2*41
=82°
In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.
∠BCE+∠CEB+EBC=180 (Sum of all the angles in a triangle is 180°)
∠BCE+90+82=180
∠BCE=180-172
∠BCE=8°
Hence if BF is an angle bisector then angle m∠BCE=8°.
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Answer:
x = 76.80°
4x - 142 = 165.18°
x/5 = 15.36°
5x/9 + 60 = 102.66°
Step-by-step explanation:
Total angle in a quadrilateral is 360
x + 4x - 142 + x/5 + (5/9)x + 60 = 360
259x/45 + - 82 = 360
259x/45 = 442
x = 76.7953668
x = 76.80°
4x - 142 = 165.18°
x/5 = 15.36°
5x/9 + 60 = 102.66°
The polynomial p(x)=x^3-6x^2+32p(x)=x 3 −6x 2 +32p, left parenthesis, x, right parenthesis, equals, x, cubed, minus, 6, x, squar
Ray Of Light [21]
Answer:
(x-4)(x-4)(x+2)
Step-by-step explanation:
Given p(x) = x^3-6x^2+32 when it is divided by x - 4, the quotient gives
x^2-2x-8
Q(x) = P(x)/d(x)
x^3-6x^2+32/x- 4 = x^2-2x-8
Factorizing the quotient
x^2-2x-8
x^2-4x+2x-8
x(x-4)+2(x-4)
(x-4)(x+2)
Hence the polynomial as a product if linear terms is (x-4)(x-4)(x+2)
Answer:
Step-by-step explanation:
There will be a fence around the garden. ... per linear foot. About how much will the fencing costs altogether? Round to the nearest hundreth. Use 3.14 for π ... The straight part of the fence will equal the diameter (d) = 32. The rounded portion will be 1/2 the circumference = (pi)d/2 = (3.14)(16)=50.24.
Answer:
Step-by-step explanation:
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