3 years ago

Find the area of triangle ABC please help asap!

Mathematics

1 answer:

Daniel [21]3 years ago

3 0

Step-by-step explanation:

The Base of the triangle= 3+6=9 units

Altitude of the triangle=6-2=4 units

Hence, Area of a triangle= Base×Altitude ×1/2

Hence, Area of the abc = 9×4×1/2=18 unit^2

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$(9x+2)*(4x^2+35x-9)=0$

we can make this...

$9x+2=0$

and

$4x^2+35x-9=0$

then...

$9x+2=0$

$\boxed{x=-\frac{2}{9}}$

$4x^2+35x-9=0$

$x=\frac{-b\pm\sqrt{b^2-4*a*c}}{2*a}$

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$x=\frac{-35\pm37}{8}$

$x_1=\frac{-35+37}{8}=\frac{1}{4}$

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$\boxed{\boxed{S=\{\frac{1}{4},-\frac{2}{9},-9\}}}$

I'm sure about my answer, don't matter the order...

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3 years ago

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4/49 times 7/13 thank you

german

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