Answer:
(a) 
(b)
Step-by-step explanation:
Let´s use Divided Differences Method of Polynomial Interpolation given by this iteration:
![f[x_k,x_k_+_1,...,x_k_+_i]=\frac{f[x_k_+_1,x_k_+_2,...,x_k_+_i]-f[x_k,x_k_+_1,...,x_k_+i_-_1]}{x_k_+_i-x_k}](https://tex.z-dn.net/?f=f%5Bx_k%2Cx_k_%2B_1%2C...%2Cx_k_%2B_i%5D%3D%5Cfrac%7Bf%5Bx_k_%2B_1%2Cx_k_%2B_2%2C...%2Cx_k_%2B_i%5D-f%5Bx_k%2Cx_k_%2B_1%2C...%2Cx_k_%2Bi_-_1%5D%7D%7Bx_k_%2B_i-x_k%7D)
k∈[0,n-i]
Thus the Newton polynomial can be written as:
![P_n_-_1(x)=f[x_0]+f[x_0,x_1](x-x_0)+f[x_o,x_1,x_2](x-x_0)(x-x_1)+...+f[x_n,x_n_-_1,...,x_1](x-x_n)(x-x_n_-_1)...(x-x_1)](https://tex.z-dn.net/?f=P_n_-_1%28x%29%3Df%5Bx_0%5D%2Bf%5Bx_0%2Cx_1%5D%28x-x_0%29%2Bf%5Bx_o%2Cx_1%2Cx_2%5D%28x-x_0%29%28x-x_1%29%2B...%2Bf%5Bx_n%2Cx_n_-_1%2C...%2Cx_1%5D%28x-x_n%29%28x-x_n_-_1%29...%28x-x_1%29)
(a) I attached you the procedure in the first table, using it we have:

Operate P(x) using the distributive property:

(b) I attached you the procedure in the second table, using it we have:

Operate P(x) using the distributive property:

Answer:
It is 80% statistically safe to conclude that the population standard deviation is less than 1.8°F
Step-by-step explanation:
The given information are;
The sample size, n = 102
The sample mean = 98.4°F
The sample standard deviation = 0.66°F
α = 0.2, ∴ α/2 = 0.1
=
= 83.267
=
= 119.589,
Which gives;

0.607 < σ <0.727
Therefore, it is 80% statistically safe to conclude that the population standard deviation is less than 1.8°F.
I don’t understand what you are trying to say
Yes because he is taller than steve who is taller than jon