8.7/2=q/4
multiply both sides by 4: q=8.7/2*4
multiply both sides by 2: 2q=8.7 times 4
refine the equation: 2q=34.8
multiply both sides by 10: 20q=348
Divide both sides by 20: 20q/20=348/20
refine the equation for the final answer: q=87/5
Answer:there are a few questions that needs answering to make your graph. 1. How many bags of popcorn can she buy with $30? 2. How much does a drink cost? 3. How many drinks can she buy with $30?
Step-by-step explanation:
<span>7 no encaja en 4, por lo que la respuesta sería cero 7 ajustes en 4, cero veces</span>
If you apply the or both
Only 1 of the students would need to know the "or both", therefore maximizing the remaining amount of students you can put in.
Gerald, let's call him, knows French AND German, so there's only one less student that knows french and german. Gerald is 1 student.
MAXIMUM:
There are now 14 monolinguistic French speakers and 16 monolinguistic German's, 30 students + Gerald=31.
Minimum:
As a bonus, the minimum is 15 students knowing french AND German and only 2 monolinguistic German speakers, so 17.
Answer:
Sum of the first 15 terms = -405
Step-by-step explanation:
a + 3d = -15 (1)
a + 8d = -30 (2)
Where,
a = first term
d = common difference
n = number of terms
Subtract (1) from (1)
8d - 3d = -30 - (-15)
5d = -30 + 15
5d = -15
d = -15/5
= -3
d = -3
Substitute d = -3 into (1)
a + 3d = -15
a + 3(-3) = -15
a - 9 = -15
a = -15 + 9
a = -6
Sum of the first 15 terms
S = n/2[2a + (n − 1) × d]
= 15/2 {2×-6 + (15-1)-3}
= 7.5{-12 + (14)-3}
= 7.5{ -12 - 42}
= 7.5{-54}
= -405
Sum of the first 15 terms = -405
