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Mazyrski [523]
3 years ago
13

4x^2+12x+4y^2-32y=27

Mathematics
1 answer:
Elis [28]3 years ago
7 0

Answer:

<h3>Find the derivitive with respect to x: </h3>

dy / dx = - 2x + 3 / 2y - 8

<h3>Find the derivitive with respect to y:</h3>

dx / dy = -2y + 8 / 2x + 3

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Geno signed up for a text messaging plan. He pays a $5.00 monthly fee and $0.04 per text message.
Marysya12 [62]

Answer:

The correct answer is [C.) 0.04r + 5.00}

Step-by-step explanation:

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Given the expression: 5x10 − 80x2 Part A: Rewrite the expression by factoring out the greatest common factor. Part B: Factor the
Darina [25.2K]

Answer:

5x^2 ( x^2 -2)(x^2 +2)(x^2+2x+2)(x^2-2x+2)

Step-by-step explanation:

5x^10 − 80x^2

The greatest common factor is 5x^2

5x^2 ( x^8 - 16)

Rewriting the parentheses

5x^2 ( x^4 ^2 - 4^2)

We notice the difference of squares (a^2 -b^2) = (a-b)(a+b)

5x^2 ( x^4 -4)(x^4+4)

Again rewriting the first parentheses

5x^2 ( x^2 ^2 -2^2)(x^4+4)

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The last term can be rewritten as(x^2+2x+2)(x^2-2x+2)

5x^2 ( x^2 -2)(x^2 +2)(x^2+2x+2)(x^2-2x+2)

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3 years ago
Pollution Rates Assignment
stepan [7]

Answer:

1. a) 4.8 lb

I) 8%

II) 0.384 lb

2. a) 12.5 lb

I) 8%

II) 1 lb

Step-by-step explanation:

Let's begin by listing out the given variables:

mass of pesticide (m) = 12 lb,

40WP (40 weight percent) means the active ingredient comprises 40% of the total mass of the pesticide

a) amount of active ingredient = mass of the pesticide * weight percentage of the active ingredient

x = 12 * 40% = 12 * 0.4

x = 4.8 lb

I. If the soil has an absorption rate of 92%, that means 8% will go into the run-off

The percentage of active ingredient that will end up in the run-off = the percentage of the active ingredient (100%) - the absorption rate

y = (100 - 92)%

y = 8%

II. amount of of active ingredient that will end up in the run-off = amount of active ingredient * the percentage of active ingredient that will end up in the run-off

z = x * y = 4.8 * 8% = 4.8 * 0.08

z = 0.384 lb

2. Let's list out the variables given, we have:

mass of pesticide = 25 lb, weight percent of active ingredient = 50% = 0.5

amount of active ingredient = mass of the pesticide * weight percentage of the active ingredient

x = 25 * 0.5

x = 12.5 lb

I. If the soil has an absorption rate of 92%, that means 8% will go into the run-off

The percentage of active ingredient that will end up in the run-off = the percentage of the active ingredient (100%) - the absorption rate

y = (100 - 92)%

y = 8%

II. amount of of active ingredient that will end up in the run-off = amount of active ingredient * the percentage of active ingredient that will end up in the run-off

z = x * y = 12.5 * 8% = 12.5 * 0.08

z = 1 lb

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4 years ago
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