Answer:
No its short 207
Step-by-step explanation:
Took the test on UsaTestPrep got it right :)
Bye loves <3
<span>The number of cell phone minutes used by high school seniors follows a normal distribution with a mean of 500 and a standard deviation of 50. what is the probability that a student uses more than 580 minutes?
Given
μ=500
σ=50
X=580
P(x<X)=Z((580-500)/50)=Z(1.6)=0.9452
=>
P(x>X)=1-P(x<X)=1-0.9452=0.0548=5.48%
</span>
100%-26%
426000*(1-0.26)^t, yearly
(0.74^(1/12))=0.74^0.083 monthly rate of decrease
Equation for calculation population
426000*(0.74^0.083)^12t
I think it should look like this 0.74^0.083 monthly rate of decrease
Answer:
$51,480
Step-by-step explanation:
30 x 33 x 52 = $51,480