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Jlenok [28]
3 years ago
7

A piece of string is 120 centimeters long.

Mathematics
1 answer:
zimovet [89]3 years ago
6 0

Answer:

1.2 meters

Step-by-step explanation:

100 centimeters = 1 meter, so... (multiply both sides by 1.2)

120 centimeters = 1.2 meters

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-23<br> Simplify your answer as much as possible.<br> =<br> X<br> ?
Murljashka [212]

Answer:

Question is not fully addressed

Step-by-step explanation:

Please put the full question otherwise, i cannot answer it

3 0
3 years ago
I really need help in this homework all of it
larisa [96]
3.
-4(-5 - b) = (1/3)(b + 16)
distribute
20 + 4b = (1/3)b + 16/3
reduce
13/3b = -44/3
divide
b = -44/13

4.
(3/5)(t + 18) = -3(2 - t)
distribute
3/5t + 54/5 = -6 + 3t
reduce
 84/5= 12/5t
divide
7 = t

I hope this helps :)
7 0
3 years ago
Sara ordered 2 slices of pizza and a 12-ounce cola and paid
Natasha_Volkova [10]

Answer: a slice of pizza cost $1.25 and a 12-ounce cola cost $0.50.

Step-by-step explanation:

Let slice of pizza cost x and a 12-ounce cola cost y.

Then Sara's order cost: 2x+y=3

and Sydney's order cost: 3x+2y=4.75

From the first equation we have: y=3-2x and put this to the second equation:

3x+2(3-2x)=4.75

3x+6-4x=4.75

x=1.25

y=3-1.25*2=0.50

Answer: a slice of pizza cost $1.25 and a 12-ounce cola cost $0.50.

5 0
3 years ago
(3k^3+4k^2-2)-(5k^2-9)-(7k^3+6k)
mr Goodwill [35]

Answer:

− 4 k3− k 2− 6 k+7

Step-by-step explanation:

I just simplified the expression.

4 0
3 years ago
Question 1: The diagonal of a rectangle, with base x, remains at a fixed
kramer

We have that The height changing rate  when the length of the base is 2 cm

dh/dt=-7.2cm/s

From the question we are told

The diagonal of a rectangle, with base x, remains at a fixed value of 3cm. If the base is increasing at a rate of 8 cm/s. at what rate is  the height changing when the length of the base is 2 cm?

Generally the Pythagoras equation for the triangle   is mathematically given

as

r^2=h^2+x^2

With r=3

Therefore

dx/dt=8cm/s

Hence

2rdr/dt=2hdh/dt+2xdx/dt\\\\\dh/dt=\frac{-x}{r^2-x^2}dx/dt

We  have

dh/dt=-2/\sqrt{5}(8)\\\\dh/dt=-7.2cm/s

Therefore

The height changing rate  when the length of the base is 2 cm

dh/dt=-7.2cm/s

For more information on this visit

brainly.com/question/23366835

4 0
3 years ago
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