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Mkey [24]
3 years ago
14

I could really use some help , ive never done this before .:,)

Mathematics
1 answer:
USPshnik [31]3 years ago
8 0

Answer:

Step-by-step explanation: This is what i can do

1. The first graph belongs to this question

3p+4\geq -14 , 1-5p\geq -39\\\\\mathrm{Isolate}\:y\:\mathrm{for}\:3y+4\ge \:-14:\quad y\ge \:-6\\\\\mathrm{Isolate}\:y\:\mathrm{for}\:1-5y\ge \:-39:\quad y\le \:8\\\\=\begin{bmatrix}y\ge \:-6\\ y\le \:8\end{bmatrix}\\\\\mathrm{1.\:Graph\:each\:inequality\:separately.}\\\mathrm{2.\:Choose\:a\:test\:point\:to\:determine\:which\:side\:of\:the\:line\:needs\:to\:be\:shaded.}\\

3.\:The\:solution\:to\:the\:system\:, will\:be\\\:the\:area\:where\:the\:shadings\:from\:each\:\\inequality\:overlap\:one\:another.\\\\\mathrm{See\:graph\:below.}\\\\\begin{bmatrix}y\ge \:-6\\ y\le \:8\end{bmatrix}\quad \mathrm{Unbounded}

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Let:

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2u + 3v = 13 \\ 5u - 4v =  - 2 \\  \\   + 8u + 12v = 52 \\  + 15u - 12v =  - 6 \\ 23u = 46 \\ u = 2 \\  \\ 2(2) + 3v = 13 \\ 4 + 3v = 13 \\ 3v = 9 \\ v = 3

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