Mike's grandmother opened a savings account in Mike's name and deposited some money into the account. The account pays an annual
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Get into ax²+bx+c=0 form
subsitute u=x⁴
x⁸-3x⁴+2=0
(x⁴)²-3(x⁴)+2=0
u²-3u+2=0
factor
(u-2)(u-1)=0
set to zero
u-2=0
u=2
u-1=0
u=1
wait, u=x⁴
2=x⁴
![\sqrt[4]{2}=x](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%7D%3Dx)
1=x⁴
+/-1=x
the subsitution is u=x⁴
and the possible values for x are -1,, and 1
subsitute u=x⁴
x⁸-3x⁴+2=0
(x⁴)²-3(x⁴)+2=0
u²-3u+2=0
factor
(u-2)(u-1)=0
set to zero
u-2=0
u=2
u-1=0
u=1
wait, u=x⁴
2=x⁴
1=x⁴
+/-1=x
the subsitution is u=x⁴
and the possible values for x are -1,
Linear equation are the equation which has the power of the unknown variable is 1. The Emily have total 2 number of dimes coin and total 6 number of nickels coin.
<h3>Given information-</h3>Emily has 8 coins in her purse totaling 50 cents
The only kinds of coins she has are nickels and dimes.
<h3>Nickel</h3>A nickel is a coin which has the value equal to the 5 cents.
<h3>Dimes</h3>A dimes is a coin which has the value equal to the 10 cents.
Suppose the number of nickel coin is <em>x </em>and the number of dimes coin is <em>y.</em>
As total coins are 8 . Thus,
......equation 1
As the total value of the cents is 50 and nickel is equal to the 5 cents whereas the dimes is equal to the 10 cents. Thus,
Put the value of the <em>x</em> from the equation 1 in the above equation.
Thus Emily have total 2 number of dimes coin.
Put this value of y in equation 1 we get,
Thus Emily have total 6 number of nickels coin.
Hence the Emily have total 2 number of dimes coin and total 6 number of nickels coin.
Learn more about the coin based problems here;