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bogdanovich [222]
3 years ago
5

What’s the answer to 14 and 18?

Mathematics
2 answers:
vladimir1956 [14]3 years ago
7 0

Answer:

SIX

Step-by-step explanation:


Shkiper50 [21]3 years ago
6 0

14)

-√9/100 = -3/10

18)

-√2.25 = - 1.5

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Wires manufactured for use in a computer system are specified to have resistances between 0.11 and 0.13 ohms. The actual measure
Marina CMI [18]

Answer:

a) P(0.11

And we can find this probability with this difference and with the normal standard table or excel:

P(-1.11

b) P(0.11 < \bar X < 0.13)

And we can use the z score defined by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using the limits we got:

z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22

z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22

And we want to find this probability:

P(-2.22< Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the resitances of a population, and for this case we know the distribution for X is given by:

X \sim N(0.12,0.009)  

Where \mu=0.12 and \sigma=0.009

We are interested on this probability

P(0.11

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(0.11

And we can find this probability with this difference and with the normal standard table or excel:

P(-1.11

Part b

We select a sample size of n =4. And since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want this probability:

P(0.11 < \bar X < 0.13)

And we can use the z score defined by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using the limits we got:

z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22

z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22

And we want to find this probability:

P(-2.22< Z

4 0
3 years ago
Read 2 more answers
There are at least 5 slices of bread left in the bag. Use p as your variable
kykrilka [37]

Answer: p ≤ 5

Step-by-step explanation: The inequality is: p ≤ 5

8 0
3 years ago
A 4-foot tree was planted in 1984. The tree grows continuously by 22% each year from this point forward. Find the height of the
nata0808 [166]

Answer:

the tree will be 11.04 feet tall

Step-by-step explanation:

4 x 0.22 (22%) = 0.88

every year it grows 0.88 foot.

0.88 x 8 = 7.04

4 + 7.04 = 11.04 feet tall

sorry if this is wrong!

3 0
3 years ago
Does anyone else have to do i-Ready
julsineya [31]

Answer:

No

Step-by-step explanation:

Does anyone have to do DELTA-MATH

7 0
3 years ago
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Verify the following identity: (csc theta -cot theta )/(sec theta -1) A. sec theta B. cos theta C. cot theta D. sin theta
alexdok [17]

Answer:

C. cot theta

Step-by-step explanation:

(csc theta -cot theta )/(sec theta -1)

csc = 1/ sin

cot = cos / sin

sec = 1 / cos

Let x = theta

(1/ sin x -cos x / sin x )/(1/ cos x -1)

Getting a common denominator in the denominator and combining terms

(1- cos x)/ sinx  / ( 1 - cos x) / cos x

(1- cosx)      (1- cosx)

----------- ÷ ------------

sinx            cos x

Copy dot flip

(1- cosx)       cosx

----------- * ------------

sinx            1 -cos x

Cancel like terms

cos x / sin x

cos / sin = cot

cot x

cot theta

3 0
3 years ago
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