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Zarrin [17]
3 years ago
5

Part A: Maria rented a coat at $285 for 3 days. If she rents the same coat for 6 days, she has to pay a total rent of $510. Writ

e an equation in the standard form to represent the total rent (y) that Maria has to pay for renting the coat for x days. (4 points)
Part B: Write the equation obtained in Part A using function notation.(2 points)

Part C Describe the steps to graph the equation obtained above on the coordinate axes. Mention the labels on the axes and the intervals. (4 points)

Mathematics
2 answers:
masha68 [24]3 years ago
5 0

Answer: A) y=75x+60

B) f(x)=75x+60

C) The point on axes are (0,60) and (-0.8,0)

Step-by-step explanation:

Since we have given that

Rented price of coat for 3 days = $285

Rented price of coat for 6 days = $510

Let x be the number of days.

Let y be the total rent.

So, equation of line would be

y-y_0=\dfrac{y_1-y_0}{x_1-x_0}(x-x_0)\\\\y-285=\dfrac{510-285}{6-3}(x-3)\\\\y-285=\dfrac{225}{3}(x-3)\\\\y-285=75(x-3)\\\\y-285=75x-225\\\\y=75x-225+285\\\\y=75x+60

B) equation using function notation is given by

f(x)=75x+60

C) Let x= 0

Then, f(x)= 60 and

let y = 0

0=75x+60

x=\dfrac{-60}{75}=-0.8

So, the point on axes are (0,60) and (-0.8,0)

TEA [102]3 years ago
3 0
Part a y=95x

Part b 285=95•3

Part c ?

Hope I helped sorry I don't know how to do the last one!
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Step-by-step explanation:

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Solution 1:

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            =  75

Mean absolute deviation= ( I 78-75 I + I 99-75 I+I 90-75 I + I 80-75 I +

                                             I 55-75 I + I 56-75 I + I 102-75 I + I 88- 75 I +

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Solution 3:

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Mean absolute deviation  = ( I 1-6 I + I 7-6 I + I 10-6 I + I 5-6 I + I 3-6 I +

                                               I 3-6 I + I 6-6 I + I 12- 6 I + I 9-6 I + I 4-6 I) /10

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                                               I 40-30 I + I 24-30 I) /10

         = (86)/10

        =  8.6

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