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Vsevolod [243]
2 years ago
14

(80 pts) Alexandra bought 4 hamburgers and 3 drinks for her family. The cost was $18.25. Tyler bought 6 hamburgers and 4 drinks

at the same fast food restaurant for $26.50. What is the total cost of one hamburger and one drink?
Mathematics
2 answers:
Step2247 [10]2 years ago
8 0
 3(4h+3d=18.25)-2(6h+4d=26.50)

12h+9d-12h-8d=54.75-53

d=1.75, use either original equation to solve for h...

4h+3(1.75)=18.25

4h+5.25=18.25

4h=13

h=3.25

So the cost of one hamburger and one drink is:

3.25+1.75=$5.00
vivado [14]2 years ago
7 0
H=hamburgers.
D=drinks

3(4h+3d=18.25) - 2(6h+4d=26.50)

12h+9d-12h-8d=54.75-53

d=1.75

4h+3(1.75)=18.25

4h+5.25=18.25

4h=13

h=3.25

cost of one hamburger and one drink is:

3.25+1.75=$5.00
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The planning value for the population standard deviation is 4330.

Given the confidence interval 20000 and 35000.

We have to find the planning value of standard deviation.

Standard deviation is measuring dispersion of data. Uniform probability distribution has two bounds a and b. The standard deviation is given by :

s=\sqrt{(b-a)^{2}/12 }.

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It is uniform in the interval so, a=20000, b=35000.

Now we have to just put the values of a and b in the above formula to get the value of standard deviation.

s=\sqrt{(35000-20000)^{2} /12}

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Learn more about standard deviation at brainly.com/question/475676

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Step-by-step explanation:

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