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jekas [21]
3 years ago
14

For

align="absmiddle" class="latex-formula"> and g(x) = x^{2} - 6, find (f * g)(x)
A. 3x^{2} - 17
B. 3x^{3} + x^{2} - 6x -6
C. 4x^{2} -6x - 8
D. 3x^{3} + x^{2} - 18x -6
Mathematics
1 answer:
mars1129 [50]3 years ago
3 0

Answer:

3x^3+x^2-18x-6

Step-by-step explanation:

f(x)= 3x+1 and g(x)= x^2 - 6

we need to find (f*g)(x)

(f*g)(x)= f(x) * g(x)

Plug in the given f(x) and g(x)

(f*g)(x)= f(x) * g(x)= (3x+1)(x^2-6)

Apply FOIL method to multiply it

(3x+1)(x^2-6)= 3x^3 -18x+x^2-6= 3x^3+x^2-18x-6

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