Two consecutive positive numberside are such that the sum of their squares is 113. Find the two numbers

Mathematics

1 answer:

PolarNik [594]3 years ago

3 0

the two consecutive numbers are 56 and 57

x+x+1=113

2x+1=113

2x=113-1

2x=112

x=112/2

x=56

therefore, x=56

x+1= 56+1= 57

You might be interested in

Jeffery is playing a game with two spinners below:

Mrrafil [7]

The <em>correct answer</em> is:

{3, 4, 5, 6, 7, 8, 9, 10, 11, 12} .

Explanation:

The sample space for rolling these two spinners is:

(1, 2), (1, 4), (1, 6), (1, 8)

(2, 2), (2, 4), (2, 6), (2, 8)

(3, 2), (3, 4), (3, 6), (3, 8)

(4, 2), (4, 4), (4, 6), (4, 8)

This gives us the sums:

3, 5, 7, 9

4, 6, 8, 10

5, 7, 9, 11

6, 8, 10, 12

As a set, these are:

{3, 4, 5, 6, 7, 8, 9, 10, 11 12}

3 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP THANK YOU

Nadya [2.5K]

<span>Simplifying 2x + 18y = 36 Solving 2x + 18y = 36 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-18y' to each side of the equation. 2x + 18y + -18y = 36 + -18y Combine like terms: 18y + -18y = 0 2x + 0 = 36 + -18y 2x = 36 + -18y Divide each side by '2'. x = 18 + -9y Simplifying x = 18 + -9y</span>

3 0

3 years ago

Given the function f(x) = √x-8 + 3 which of the following is the value of f(24)

kvasek [131]

Answer:

The answer is 7.

Step-by-step explanation:

You have to substitute the value of x into the function :

$f(x) = \sqrt{x - 8} + 3$