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3 years ago

11

twice the sum of a number and 2 is equal to three times the difference of the number and 8. Find the number.

1 answer:

Leto [7]3 years ago

4 0

Answer: x = -22

Step-by-step explanation:

Look at picture!

You might be interested in

What number two numbers when multiplied equal 24 but when added equal -4

madam [21]

Since it says when Added they are a negative and when multiplied they are positive, we know our two numbers are negative.
think of all multiples of 24
6 and 4
8 and 3
12 and 2
24 and 1
however, none of our choices here would be correct.

5 0

3 years ago

What's the answer..............

ruslelena [56]

Aye the Answer is D ~hope that helps :)

7 0

3 years ago

A triangle can have one right angle.<br> a. True<br> b. False

iragen [17]

True because a triangle must have 3 angles that add up to 180 degrees and, since a right angle is 90 degrees, it cannot have 2 right angles

3 0

4 years ago

A common blood test performed on pregnant women to screen for chromosome abnormalities in the fetus measures the human chorionic

goldfiish [28.3K]

Answer:

(a) The proportion of women who are tested, get a negative test result is 0.82.

(b) The proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

Step-by-step explanation:

The Bayes' theorem states that the conditional probability of an event <em>E</em> $_{i}$ , of the sample space <em>S,</em> given that another event <em>A</em> has already occurred is:

$P(E_{i}|A)=\frac{P(A|E_{i})P(E_{i})}{\sum\liits^{n}_{i=1}{P(A|E_{i})P(E_{i})}}$

The law of total probability states that, if events <em>E</em>₁, <em>E</em>₂, <em>E</em>₃... are parts of a sample space then for any event <em>A</em>,

$P(A)=\sum\limits^{n}_{i=1}{P(A|B_{i})P(B_{i})}$

Denote the events as follows:

<em>X</em> = fetus have a chromosome abnormality.

<em>Y</em> = the test is positive

The information provided is:

$P(X)=0.04\\P(Y|X)=0.90\\P(Y^{c}|X^{c})=0.85$

Using the above the probabilities compute the remaining values as follows:

$P(X^{c})=1-P(X)=1-0.04=0.96$

$P(Y^{c}|X)=1-P(Y|X)=1-0.90=0.10$

$P(Y|X^{c})=1-P(Y^{c}|X^{c})=1-0.85=0.15$

(a)

Compute the probability of women who are tested negative as follows:

Use the law of total probability:

$P(Y^{c})=P(Y^{c}|X)P(X)+P(Y^{c}|X^{c})P(X^{c})$

$=(0.10\times 0.04)+(0.85\times 0.96)\\=0.004+0.816\\=0.82$

Thus, the proportion of women who are tested, get a negative test result is 0.82.

(b)

Compute the value of P (X|Y) as follows:

Use the Bayes' theorem:

$P(X|Y)=\frac{P(Y|X)P(X)}{P(Y|X)P(X)+P(Y|X^{c})P(X^{c})}$

$=\frac{(0.90\times 0.04)}{(0.90\times 0.04)+(0.15\times 0.96)}$

$=0.20$

Thus, the proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

6 0

3 years ago

For any two documents x and z, define k(x; z) to equal the number of unique words that occur in both x and z (i.e., the size of

liq [111]

Answer:

Yes, the function is a kernel

Step-by-step explanation:

Given

Document x an z

Function definition! k(x:z)

We want to show that the above is a kernel.

To do this, we'll explicitly construct feature vectors φ(x) and φ(z)

This gives;

K(x,z) =φ(x)·φ(z).

Given than any document; say x and z

A vocabulary V can be constructed.

Vocabulary V must have a finite size of words in the document set..

The feature mapping is constructed as φ(x) for x by the following:

For the kth word wk in V, if wk appears in document x, assign φ(x) k(the kth element ofφ(x)) to be 1; else φ(x)k to 0.

Then the number of unique words common in x and z is φ(x)·φ(z), giving us the kernel

.

7 0

3 years ago