Question

Easy Fast Question PLease HElp Multiply -2x^2(3x^3-5x^2+6x-1)

Answer 1

Answer:

$6x^5-10x^4+12x^3-2x^2$

Step-by-step explanation:

We are the following expression and we are to expand it by multiplying the term outside the parenthesis with terms inside it:

[ t e x ] - 2 x ^ 2 ( 3 x ^ 3 - 5 x ^ 2 + 6 x - 1 ) [ / t e x]

Multiplying the term [ t e x ] - 2 x ^ 2 [/ t e x ] with each of the terms inside the brackets to get:

$6x^5-10x^4+12x^3-2x^2$

Note that the exponents are added when multiplied and since each terms has a different exponent so they cannot be added or subtracted.

Answer 2

Answer:

The correct answer is -6x^5 + 10x^4 - 12x^3 + 2x^2

Step-by-step explanation:

The given expression is -2x^2(3x^3-5x^2+6x-1)

Multiply each term by -2x^2, we get

To evaluate  the expression

-2x^2 *3x^3 -(-2x^2)* 5x^2 + (-2x^2)*6x- (-2x^2)*1

-6x^5 + 10x^4 - 12x^3 + 2x^2

Therefore the correct answer is -6x^5 + 10x^4 - 12x^3 + 2x^2