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tatiyna
3 years ago
10

I need help finding x and y

Mathematics
1 answer:
leonid [27]3 years ago
5 0
I 100% know I got X correct but you might have to double check my Y.
X = 10
Y= 20 sq root of 3 / 3

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Find the area of the blue sector(s). The diameter is 14.
pav-90 [236]

The area of the entire circle is pi*(7)^2, or 49pi.


Due to the 90 degree angle, the area of the larger blue sector is


90

------- * 49 pi = 49/4 units^2

360


The area of the smaller blue sector is


48

------- 49 pi = (2/15)(49 pi) = 98 pi/15 units^2

360


The total area of the blue sectors is the sum of 98 pi/15 and 49 pi/4 (units^2):


59 units^2

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3 years ago
The average rainfall in inches in Miami from January to May is 1.61, 2.24, 2.99, 3.15, 5.35, and 9.68 while it is 2.24, 2.8, 3.0
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The answer is 100% A
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What is the y-intercept of the line given by the equation below? Enter you answer as an ordered pair.
NikAS [45]

Answer:

0, 7 )

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 8x + 7 ← is in slope- intercept form

with y- intercept c = 7 ⇒ (0, 7 )

8 0
3 years ago
John made 3 more free throws than Jose. The
jeyben [28]
25-3=22

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3 years ago
The expected number of typographical errors on a page of a certain magazine is .2. What is the probability that an article of 10
Pavel [41]

Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

N\sim Pois(0.2)

P(N=r)=\frac{e^{-np}(np)^r}{r!}

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}

P(N=0)=\frac{e^{-0.2}}{1}

P(N=0)=e^{-0.2}

P(N=0)=0.8187

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute r\geq 2 in formula,

P(N\geq 2)=1-P(N

P(N\geq 2)=1-[P(N=0)+P(N=1)]

P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]

P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]

P(N\geq 2)=1-[0.8187+0.1637]

P(N\geq 2)=1-0.9825

P(N\geq 2)=0.0175

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

6 0
3 years ago
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