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lozanna [386]
3 years ago
12

6y^-4 using only positive exponents

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
6 0
Y⁻¹ = \frac{1}{y^{4} }

y^{-4} =  \frac{1}{y^{4} }

6*\frac{1}{y^{4} }
= \frac{6}{y^{4} }
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Which term completes the product so that it is the difference of squares?
FromTheMoon [43]

Answer:

the answer is  3

Step-by-step explanation:

(-5x-3)(-5x+3)=(5x)^2 - (3)^2

A difference of squares is the difference of two squared terms.

We have

a^2 - b^2

We can factorize the difference of squared terms like this:

a^2-b^2 = (a+b)(a-b)

We have (-5x-3)(-5x+3)

Lets prove it:

(-5x-3)(-5x+3) = (-5x*-5x)+(-5x*3)+(-3*-5x)+(-3*3)

(-5x-3)(-5x+3) = 25x^2+(-15x)+(15x)+(-9)

(-5x-3)(-5x+3) = 25x^2-15x+15x-9

(-5x-3)(-5x+3) = 25x^2-9

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6 0
4 years ago
Read 2 more answers
Simplify
bixtya [17]

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Step-by-step explanation:

the square root of any negative value results in an imaginary number, 'i'

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'i' is equal to -1

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6 0
3 years ago
If JK is the midsegment of triangle GHI, find x
Nady [450]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
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Step-by-step explanation:

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so the anwser is 60

7 0
3 years ago
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Anestetic [448]

Answer:

5x

8y

Step-by-step explanation:

3 0
3 years ago
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