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Paladinen [302]
3 years ago
6

What are the coordinates of the midpoint of the segment whose endpoints are A (-1, -2) and B (6, 12)

Mathematics
1 answer:
Klio2033 [76]3 years ago
5 0

<u>Answer:</u>

Mid point = (\frac{5}{2} ,5)

<u>Step-by-step explanation:</u>

We are given the coordinates of the end points of a line segment AB and we are to find the coordinates of its mid point.

The coordinates of the end points are: A (-1, -2) and B (6, 12).

We know the formula of the mid point:

Mid point = (\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )

So putting in the given values to find the mid point of line segment AB:

Mid point = (\frac{-1+6}{2} ,\frac{-2+12}{2} ) = (\frac{5}{2} ,5)

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guse lagrange multipliers to find the maximum or minimum values of the function subject to the given constraint. (if an answer d
Novosadov [1.4K]

Therefore the maximum value of function f(x,y,z)=x^{2} y^{2} z^{2} =1/27

And the minimum value is 0

<h3>What is function?</h3>

function, in mathematics, an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable) (the dependent variable) (the dependent variable) (the dependent variable). Mathematics uses functions frequently, and functions are essential for specifying physical relationships in the sciences.

Here,

The function is given as:

f(x,y,z)=x^{2} y^{2} z^{2}

x^{2} +y^{2}+ z^{2}=1

=>x^{2} +y^{2}+ z^{2}-1=0

Using Lagrange multiplies, we have:

L(x,y,z,λ)=f(x,y,z) +λ(0)

Substitute f(x,y,z)=x^{2} y^{2} z^{2}  and x^{2} +y^{2}+ z^{2}-1=0

Differentiate

L(x)=2xy^{2} z^{2}+2λx

L(y)=2yx^{2} z^{2}+2λy

L(z)=2zx^{2} y^{2}+2λz

L(λ)=x^{2} +y^{2}+ z^{2}-1

Equating to 0

2xy^{2} z^{2}+2λx =0

2yx^{2} z^{2}+2λy = 0

2zx^{2} y^{2}+2λz = 0

x^{2} +y^{2}+ z^{2}-1 = 0

Factorize the above expressions

2xy^{2} z^{2}+2λx =0

2x(y^{2} z^{2}+λ)=0

2x=0 and (y^{2} z^{2}+λ)=0

x=0 and  y^{2} z^{2}= -λ

2yx^{2} z^{2}+2λy = 0

2y(x^{2} z^{2}+λ)=0

2y=0 and (x^{2} z^{2}+λ)=0

y=0 and  x^{2} z^{2}= -λ

2zx^{2} y^{2}+2λz = 0

2z(y^{2} x^{2}+λ)=0

2z=0 and (x^{2} y^{2}+λ)=0

z=0 and  x^{2} y^{2}= -λ

So we have ,

x=0 and  y^{2} z^{2}= -λ

y=0 and  x^{2} z^{2}= -λ

z=0 and  x^{2} y^{2}= -λ

The above expression becomes

x=y=z=0

This means that,

x^{2} +y^{2}+ z^{2}=1

x^{2} +x^{2}+ x^{2} =1 \\3x^{2 } =1

x= ±1/\sqrt{3}

So,

y= ±1/\sqrt{3}

z= ±1/\sqrt{3}

The critic points are

x=y=z=±1/\sqrt{3}

x=y=z=0

Therefore the maximum value of function f(x,y,z)=x^{2} y^{2} z^{2} =1/27

And the minimum value is 0

To know  more about function , visit

brainly.com/question/12426369

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3 0
1 year ago
-5y y=-2 -3x 6y=-12 substitution
IrinaK [193]
The answer would be x=4 and y=-2.
5 0
3 years ago
How many times bigger is the 45,776 than 45.776
sweet [91]

Answer:

54

Step-by-step explanation:

7 0
3 years ago
The quotient of (x4 + 5x3 – 3x – 15) and a polynomial is (x3 – 3). What is the polynomial?
solmaris [256]

Answer:

Dividend

 =x^4 + 5 x^3 - 3 x - 15

Divisor

=x^3-3

The rule of division of polynomial which is same as division of real numbers states that

Dividend = Divisor × Quotient + Remainder

The division process is shown below.

Quotient = x+5

Remainder =0

3 0
3 years ago
Read 2 more answers
Students are given 3 minutes to complete each multiple-choice question on a test and 8 minutes for each free-response question.
Alja [10]

The value that could replace variable x in the table is (15 - m)8

<h3 /><h3>How to the value of x in an expression ?</h3>

The students are given 3 minutes to complete each multiple choice question on a test and 8 minutes for each free response question.

From the table, the time to answer the whole multiple choice question is as follows:

total time = 3m

From the table, the total time taken to answer the free response question is as follows:

total time = (15 - m)8

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5 0
2 years ago
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