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gavmur [86]
3 years ago
11

Hi! Does anybody know how to do this?

Mathematics
1 answer:
nasty-shy [4]3 years ago
6 0

Answer:

4x^2 -6x^2  - 6x  +3x+3 -4

Step-by-step explanation:

3 - 6x +4x^2 +3x -6x^2 -4

To put like terms next to each other, put the highest powers first down to the lowest powers

4x^2 -6x^2  - 6x  +3x+3 -4

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Write the equation of the sphere in standard form. x^2 + y^2 + z^2 + 2x − 4y − 6z = 22
madam [21]

The equation x^{2} +y^{2} +z^{2} +2x-4y-6z=22  in standard form looks like (x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}.

Given equation of sphere be x^{2} +y^{2} +z^{2} +2x-4y-6z=22.

We are required to express the given equation in the standard form of the equation of sphere.

Equation is basically relationship between two or more variables that are expressed in equal to form. Equation of two variables look like ax+by=c. It may be linear equation,quadratic equation, cubic equation or many more depending on the powers of variables. The standard form of the equation of sphere looks like  x^{2} +y^{2} +z^{2} =r^{2}.

The given equation is x^{2} +y^{2} +z^{2} +2x-4y-6z=22.

We have to break 22 which is in right side into various parts according to the left side of the equation.

x^{2} +y^{2} +z^{2} +2x-4y-6z=-1-4-9+36

x^{2} +y^{2} +z^{2} +2x-4y-6z+1+4+9=36

x^{2} +1+2x+y^{2}+4-4y+z^{2} +9-6z=36

x^{2} +(1)^{2} +2*1*x+y^{2} +(2)^{2} -2*2y+z^{2} +(3)^{2} -2*3z=36

(x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}

Hence the equation x^{2} +y^{2} +z^{2} +2x-4y-6z=22  in standard form looks like (x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}.

Learn more about equations at brainly.com/question/2972832

#SPJ4

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