Question

Right triangle ABC has three sides with lengths AB= 119, BC = 169, CA= 120. Find the value of cos C. hint: draw and label the triangle. The hypotenuse is always the longest.

Answer 1

Answer:

$\cos(C)=\frac{120}{169}$

Step-by-step explanation:

The triangle is shown in the attachment.

Recall that;

$\cos(C)=\frac{Adjacent}{Hypotenuse}$

This implies that;

$\cos(C)=\frac{|AC|}{|BC|}$

We substitute the values into the ratio to obtain

$\cos(C)=\frac{120}{169}$