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Serhud [2]
3 years ago
6

Find the sale price to the nearest cent. $4.30 makeup; 40% discount; 6% tax

Mathematics
1 answer:
katrin [286]3 years ago
7 0

Answer:

Sale price is $2.58.

Paid with tax is $2.73

Step-by-step explanation:

If the make-up is originally $4.30 and you receive a 40% discount. This means you'll pay 60% of the price since 100-40=60.

To find this price, 60% as 0.6 is multplied with the price. 0.6*4.30 = $2.58

This is the sale price.

When you pay you will pay 6% tax or 0.06 of the price. Find this by multiplying $2.58 by 1.06.

2.58(1.06) = $2.73

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I need help what is the correct awnser radius and diameter
geniusboy [140]

Answer:

Hi! Here is what I have: r=10.6 and d= 21.2

Step-by-step explanation:

1: Multiply your radius by 2 so (10.6 x 2)

2: Get your answer which is 21.2 (from the calculator)

3: The first choice is the correct answer.

Hope this helps!

4 0
3 years ago
What is the answer to 4(5x+8+3p)
il63 [147K]
To simplify this use the distributive property.

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5 0
3 years ago
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Zach read a book for 10 minutes every weekend in the first month, 20 minutes in the second month, 40 minutes in the third month,
siniylev [52]
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3 years ago
4 more than one third of a number n is 6. An equation is? The solution is n =?
harkovskaia [24]

Answer:

 \frac{1}{3}n  + 4  = 6  

6

Step-by-step explanation:

Given problem:

      4 more than one third of a number n is 6

Unknown:

The equation = ?

Solution of the number  = ?

Solution:

 let the number  = n

So, 4 more than one third of a number;

  One third of n = \frac{1}{3}n

  4 more;

                \frac{1}{3}n  + 4

   is 6;

             \frac{1}{3}n  + 4  = 6   (equation of the expression)

Let us now solve the equation:

                         \frac{1}{3}n  + 4  = 6  

                    \frac{1}{3}n = 6 - 4

                   \frac{1}{3}n = 2

                     n = 6

5 0
3 years ago
Solve the equation by completing the square.Round to the nearest hundredth if necessary. X^2–x–7=0
lesya [120]
NOTE:  \left(x-\dfrac{1}{2}\right)^2=x^2-x+\dfrac{1}{4}

x^2-x-7=0 \\ \\ \underbrace{x^2-x+\frac{1}{4}}_{\left(x-\frac{1}{2}\right)^2}-7\dfrac{1}{4}=0 \\ \\  \\ \left(x-\frac{1}{2}\right)^2=7\frac{1}{4}=\frac{29}{4} \qquad /\sqrt{}\\ \\  \left|x-\frac{1}{2}\right|=\dfrac{\sqrt{29}}{2} \\ \\  x_1=\dfrac{1}{2}-\dfrac{\sqrt{29}}{2} \approx  -2.19 \\ \\ x_2=\dfrac{1}{2}+\dfrac{\sqrt{29}}{2} \approx 3.19

ANSWER:  c)

5 0
3 years ago
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