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3 years ago

What protocol is used to access directory listings within active directory or other directory services?

Computers and Technology

1 answer:

zalisa [80]3 years ago

3 0

The LDAP protocol is used to access directory listings within active directory or other directory services.

LDAP stands for Lightweight Directory Access Protocol. The function of this protocol is to enale access to an existing direcory. LDAP is based on a client-server model.

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Convert each of the following for loops into an equivalent while loop. (You might need to rename some variables for the code to

MAVERICK [17]

Answer:

~CaptnCoderYankee

Don't forget to award brainlyest if I got it right!

Download txt

5 0

3 years ago

Zohan uses the following analogy to describe a concept of object-oriented programming. A button can have many uses. When it is p

Vika [28.1K]

Answer:

Polymorphism

Explanation:

You can have a basic button class that gets inherited by other classes.

class Button {

function pushButton(){}

}

class ElevatorButton extends Button{};

class BigRedButton extends Button{};

With these new classes, they inherit from the basic button class. They can decide what happens when the method pushButton() is called.

You don't need to worry about what pushButton() actually does, you can just call it if the object is of the type "Button" and you can expect it to work.

4 0

2 years ago

What could be a summary sentence or phrase that captures your writing experience?

Natasha2012 [34]

Answer:

A summary sentence should brief the whole content “what so ever the length of the original content” may be. 

For example, if you take a story, moral will be the good example of summary. One another example is when the teacher taught concept in the classroom, in the last few minutes of the class the teacher would brief the whole into smaller points. 

Even nowadays, people go and visit movies only after seeing the review online. So once again the review is a small brief about the movie in one or two lines. It should be crisp, use cherry-picked words, etc.

3 0

2 years ago

Review universal data models and discuss how these are being used more widely today. Does a data modeling project using a packag

adell [148]

Answer:

2. A data modelling project using a packaged data model REQUIRES A GREATER SKILL than a project not using a packaged data model.

Explanation:

1a. Review of universal models:

A data model is an abstract model that organizes elements of data and standardizes how they relate to one another and to the properties of real world entities. It has become the standard approach used towards designing databases.

A universal data model is a template data model that can be reused as a starting point or a building block to jump-start development of a data modelling project, industry specific model, logical data models.

1b. Discuss how these are being used more widely today.

*Universal data models helps professional reduce development time, improve consistency and standardization while achieving high quality models.

*Higher quality: just as architects consider blue prints before constructing a building, one should also consider data before building an app. A data model helps define the problem, enabling one to consider different approaches and choose best ones.

*By properly modelling and organization's data, the database designer can eliminate data redundancies (needless repetitions) which are a key source for inaccurate information and ineffective systems.

2. Greater and advanced skills are adequate and required when data modelling project is done using packaged data model while fewer skills are required when data modelling is done without packaged data model.

7 0

2 years ago

Read 2 more answers

(a) Store last 7 digits of your student ID in a vector (7 element row or column vector). Write a MATLAB code which creates a 7x7

astra-53 [7]

Answer:

MATLAB code explained below with appropriate comments for better understanding

Explanation:

clc

clear all

ID = [1 2 3 4 5 6 7]; % Replace this with your student ID

%(a)

A = zeros(7);

for i=1:7

A(i,i)= ID(i);

end

fprintf('A =\n');

disp(A);

B = diag(ID);

fprintf('B =\n');

disp(B);

fprintf('Both A and B are same\n');

%(b)

if(mod(A(6,6),2)==0)

fprintf('A(6,6) is even\n');

else

fprintf('A(6,6) is odd\n');

end

%(c)

if(A(3,3)>0)

fprintf('A(3,3) is positive\n');

else if(A(3,3)<0)

fprintf('A(3,3) is negative\n');

else

fprintf('A(3,3)=0\n');

end

%(d)

fprintf('\nRequired series : ');

n = 35;

while n>=0

fprintf('%i',n);

if(n>0)

fprintf(', ');

end

n = n - 5;

end

fprintf('\n');

%(e)

n = input('\nInput an integer : ');

fprintf('%i! = ',n);

F = 1;

while n>1

F = F * n;

n = n - 1;

end

fprintf('%i\n',F);

%(f)

clear all

x = [3 7 2 1];

y = [4 3 9 1];

A = 0;

C = x(1);

for i=1:length(x)

A = A + x(i)*y(i);

B(i) = x(i)/y(i);

if(min(x(i),y(i))<C)

C = min(x(i),y(i));

end

C = 1/C;

fprintf('\nA = %i\n',A);

fprintf('B = ');

disp(B)

fprintf('C = %0.5g\n',C);

%(g)

clear all

A = randi([5 25],[1,10]);

maxA = A(1);

for i = 2:10

if(maxA<A(i))

maxA = A(i);

end

minA = A(1);

i = 2;

while i<11

if(minA>A(i))

minA = A(i);

end

i = i+1;

end

fprintf('\nA = ');

disp(A);

fprintf('maxA = %i\n',maxA);

fprintf('minA = %i\n',minA);

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%output

A =

1 0 0 0 0 0 0

0 2 0 0 0 0 0

0 0 3 0 0 0 0

0 0 0 4 0 0 0

0 0 0 0 5 0 0

0 0 0 0 0 6 0

0 0 0 0 0 0 7

B =

1 0 0 0 0 0 0

0 2 0 0 0 0 0

0 0 3 0 0 0 0

0 0 0 4 0 0 0

0 0 0 0 5 0 0

0 0 0 0 0 6 0

0 0 0 0 0 0 7

Both A and B are same

A(6,6) is even

A(3,3) is positive

Required series : 35, 30, 25, 20, 15, 10, 5, 0

Input an integer : 6

6! = 720

A = 52

B = 0.7500 2.3333 0.2222 1.0000

C = 1

A = 25 14 7 10 13 17 10 17 19 9

maxA = 25

minA = 7

5 0

2 years ago