Complete Question
In a list of 15 households, 9 own homes and 6 do not own homes. Four households
are randomly selected from these 15 households. Find the probability that the
number of households in the sample which own homes is exactly 3
Answer:
Step-by-step explanation:
From the question we are told that
The number of household is n = 15
The number of household that own homes is k = 9
The number of household that do not own homes is u = 6
The number of households randomly selected is q = 4
Generally the number of ways of selecting 3 household from the total number of 9 households that own homes is mathematically represented as
Here C stands for combination hence we would be making use of the combination feature in our calculator
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Generally the number of ways of selecting 1 household from the total number of 6 households that do not own homes is mathematically represented as
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Generally the number of ways of selecting 4 household from the total number of 15 households on the list is mathematically represented as
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Generally the probability that the number of households in the sample which own homes is exactly 3 is mathematically represented as
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X is here represent the number of household in the selected sample that own homes
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