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3 years ago

How do I solve 4 sqrt 2?

Mathematics

1 answer:

Vadim26 [7]3 years ago

8 0

Exact Form: 2√2. Decimal Form: 2.82842712...

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Two sides of a rectangle are the same length, r. The other two sides are each 4 meters.

exis [7]

Answer:

4 times 4 plus 10

Step-by-step explanation:

there are waaaay more ways than just this there is

( 8 times 2 ) plus ( 5 times 2 )

and

( 5 plus 5 ) plus 16

plz mark me as brainiest

5 0

3 years ago

Each face of a six-sided cube is painted a different color. The cube is rolled twice and a coin is flipped. How many different p

Vaselesa [24]

Answer:

Step-by-step explanation:

There are 6 possible outcomes for the first roll, 6 possible outcomes for the second roll, and 2 possible outcomes for the coin flip. Since all of the events are independent, you can simply multiply these together to get a total of 72 outcomes. Hope this helps!

7 0

3 years ago

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Alice waters her plants every 2 days

snow_lady [41]

What is the question?

4 0

2 years ago

Help me find the answer

RUDIKE [14]

X= 14

2(X+4) = 2x+8
3x-6 = 2x+8
-6=2x-3x+8
-14 = -1x
X=14

6 0

2 years ago

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The given line segment has a midpoint at (3, 1).

Katena32 [7]

Answer:

$y=\frac{1}{3}x$

Step-by-step explanation:

The given line segment has a midpoint at (3, 1) and goes through (2, 4), (3, 1), and (4, -2). We can use any two of the three points to calculate the equation of the line. Let us use the points (2, 4) and (4, -2)

Therefore the line goes through (2, 4) and (4, -2). The equation of a line passing through $(x_1,y_1)\ and\ (x_2,y_2)$ is:

$\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}$ .

Therefore the line passing through (2, 4) and (4, -2) has an equation:

$\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}\\\frac{y-4}{x-2}=\frac{-2-4}{4-2}\\\frac{y-4}{x-2}=\frac{-6}{2}\\y-4=x-2(-3)\\y-4=-3x+6\\y=-3x+10$

Comparing with the general equation of line: y = mx + c, the slope (m) = -3 and the intercept on the y axis (c) = 10

Two lines are said to be perpendicular if the product of their slope is -1. If the slope of line one is m1 and the slope of line 2 = m2, then the two lines are perpendicular if:

$m_1m_2=-1$ .

Therefore The slope (m2) of the perpendicular bisector of y = -3x + 10 is:

$m_1m_2=-1\\-3m_2=-1\\m_2=\frac{1}{3}$

Since it is the perpendicular bisector of the given line segment, it passes through the midpoint (3, 1). The equation of the perpendicular bisector is:

$\frac{y-y_1}{x-x_1}=m\\\frac{y-1}{x-3}=\frac{1}{3}\\ y-1= \frac{1}{3}(x-3)\\ y-1=\frac{1}{3}x-1\\y=\frac{1}{3}x$

the equation, in slope-intercept form, of the perpendicular bisector of the given line segment is $y=\frac{1}{3}x$

7 0

3 years ago

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