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3 years ago

Could someone help me with this question.

Mathematics

2 answers:

dolphi86 [110]3 years ago

8 0

I think it’s C. I don’t really know this but I thinks it’s 80.

vfiekz [6]3 years ago

5 0

Answer:

Step-by-step explanation:

The measure of an inscribed angle is half the measure of its intercepted arc, that is

∠ GHI = 0.5 × arc GI = 0.5 × 80° = 40° → D

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The graph below represents the water path of a fire hose.

tekilochka [14]

Step-by-step explanation:

The x intercept is 42.

The 42 tells us where the water coming from the hose is touching the ground.

5 0

2 years ago

Read 2 more answers

Find the distance from the point (-4, 4) to the line y=-2x+1 . Round your answer to the nearest tenth.

kati45 [8]

Answer:

5 units.

Step-by-step explanation:

In order to find the distance between the line y = -2x + 1 and the point (-4, 4), we need to find the position of the line at x = -4. Shortest distance between two objects is a straight line, right?

So y = -2(-4) + 1 = 9; (-4, 9).

Finding the distance between (-4, 4) and (-4, 9) gives us the answer of 5.

5 0

3 years ago

Read 2 more answers

Determine if triangle ABC with coordinates A (0, 2), B (2, 5), and C (−1, 7) is an isosceles triangle. Use evidence to support y

kirill115 [55]

Answer:

The triangle ABC is an isosceles right triangle

Step-by-step explanation:

we have

The coordinates of triangle ABC are

A (0, 2), B (2, 5), and C (−1, 7)

we know that

An isosceles triangle has two equal sides and two equal internal angles

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

substitute in the formula

$d=\sqrt{(5-2)^{2}+(2-0)^{2}}$

$d=\sqrt{(3)^{2}+(2)^{2}}$

$dAB=\sqrt{13}\ units$

step 2

Find the distance BC

substitute in the formula

$d=\sqrt{(7-5)^{2}+(-1-2)^{2}}$

$d=\sqrt{(2)^{2}+(-3)^{2}}$

$dBC=\sqrt{13}\ units$

step 3

Find the distance AC

substitute in the formula

$d=\sqrt{(7-2)^{2}+(-1-0)^{2}}$

$d=\sqrt{(5)^{2}+(-1)^{2}}$

$dAC=\sqrt{26}\ units$

step 4

Compare the length sides

$dAB=\sqrt{13}\ units$

$dBC=\sqrt{13}\ units$

$dAC=\sqrt{26}\ units$

$dAB=dBC$

therefore

Is an isosceles triangle

Applying the Pythagoras Theorem

$(AC)^{2} =(AB)^{2}+(BC)^{2}$

substitute

$(\sqrt{26})^{2} =(\sqrt{13})^{2}+(\sqrt{13})^{2}$

$26=13+13$

$26=26$ -----> is true

therefore

Is an isosceles right triangle

8 0

3 years ago

Which of the following is an inscribed angle in the diagram below?

shutvik [7]

Answer:

Step-by-step explanation:

8 0

2 years ago

I need help pls thank y

otez555 [7]

What do you need help with

5 0

2 years ago