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3 years ago

I need answer correct ASAP Please!!!

Mathematics

2 answers:

Brums [2.3K]3 years ago

7 0

Answer:

cos(m∠B) = 2√5/5

Step-by-step explanation:

Easiest way is to guess and check on this problem. When you take the cos(m∠B), you would get 6/3√5, rationalized to 2√5/5. That would be the correct answer.

ELEN [110]3 years ago

4 0

Answer:

Option 1

Step-by-step explanation:

Cos B = $\frac{adjacent}{hypotenuse}$

Where adjacent = 6, Hypotenuse = 3√5

Cos B = $\frac{6}{3\sqrt{5} }$

Cos B = $\frac{2}{\sqrt{5} }$

Cos B = $\frac{2\sqrt{5} }{5}$

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The edges of a cube are 5 centimeters each and the diagonal of a face is approximately 7 centimeters. What is the approximate ar

Naddika [18.5K]

Answer:

Step-by-step explanation:

5x7=35. Unfortunately I can't show you a model to explain further.

4 0

2 years ago

Grace started her own landscaping business. She charges $6 an hour for mowing lawns and $11 per hour for pulling weeds. In Septe

valkas [14]

Answer:

$477

Step-by-step explanation:

63 hours x $6 = $378

9 hours x $11 = $99

378+99= $477

3 0

3 years ago

Solve for F: C=5(F-32)/9

puteri [66]

C = 5(F-32)/9 Multiply each side by 9
9C = 5(F-32) Distribute
9C = 5F - 160 Add 160 to each side
9C + 160 = 5F Divide each side by 5
9/5C + 32 = F

5 0

2 years ago

An article in Knee Surgery, Sports Traumatology, Arthroscopy, "Arthroscopic meniscal repair with an absorbable screw: results an

igomit [66]

Answer:

Mean = 1.57

Variance=0.31

Step-by-step explanation:

To calculate the mean and the variance of the number of successful surgeries (X), we first have to enumerate the possible outcomes:

1) Both surgeries are successful (X=2).

$P(e_1)=0.90*0.67=0.603$

2) Left knee unsuccessful and right knee successful (X=1).

$P(e_2)=(1-0.9)*0.67=0.1*0.67=0.067$

3) Right knee unsuccessful and left knee successful (X=1).

$P(e_3)=0.90*(1-0.67)=0.9*0.33=0.297$

4) Both surgeries are unsuccessful (X=0).

$P(e_4)=(1-0.90)*(1-0.67)=0.1*0.33=0.033$

Then, the mean can be calculated as the expected value:

$M=\sum p_iX_i=0.603*2+0.067*1+0.297*1+0.033*0\\\\M=1.206+0.067+0.297+0\\\\M=1.57$

The variance can be calculated as:

$V=\sum p_i(X_i-\bar{X})^2\\\\V=0.603(2-1.57)^2+(0.067+0.297)*(1-1.57)^2+0.033*(0-1.57)^2\\\\V=0.603*0.1849+0.364*0.3249+0.033*2.4649\\\\V=0.1115+0.1183+0.0813\\\\V=0.3111$

3 0

3 years ago

Help me guys please need to finish this ASAP

mezya [45]

Answer:

B Wednesday

Step-by-step explanation: Don't cheat on nwea btw

6 0

2 years ago

Read 2 more answers