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Natali [406]
3 years ago
5

Solve attachment EASY POINTS

Mathematics
1 answer:
natita [175]3 years ago
3 0

-px + r = -8x - 2

Add 2 to both sides

-px + r + 2 = -8x

Add px to both sides

r + 2 = -8x + px

Divide both sides by p - 8

\frac{r + 2}{p - 8} = x

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What is the value of StartFraction 1.6 times 10 Superscript 14 Baseline Over 3.2 times 10 Superscript 7 Baseline EndFraction in
Helga [31]

Answer:

5.0 times 10 Superscript 6

Step-by-step explanation:

What is the value of StartFraction 1.6 times 10 Superscript 14 Baseline Over 3.2 times 10 Superscript 7 Baseline?

This is represented mathematically as:

1.6 × 10¹⁴/ 3.2 × 10⁷

Solving for this

1.6 × 10¹⁴/ 3.2 × 10⁷

= [1.6/3.2] × 10¹⁴-⁷

= 5 × 10⁶

= 5.0 times 10 Superscript 6

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3 years ago
Given congruent triangles name the corresponding sides and corresponding angles
Alborosie

Answer:

See explanation

Step-by-step explanation:

Given \triangle ABC\cong \triangle ADC

According to the order of the vertices,

  • side AB in triangle ABC (the first and the second vertices) is congruent to side AD in triangle ADC (the first and the second vertices);
  • side BC in triangle ABC (the second and the third vertices) is congruent to side DC in triangle ADC (the second and the third vertices);
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6 0
4 years ago
15-29=
Dominik [7]

Answer:

15-29= -14

(I need the explanation most importantly)

14+(-4) - 8 =10-8=2

(Explanation please)

-8.4 - (19.5.) = - 27.9, (just add them to each other and write -, because both have - in front of them)

(Explanation)

-15 + 8 - (-19.7) = - 7+19,7=12,7 (there is + and - so it will became - 7, and at next there is two - which will turn them into +)

(Explanation)

29.45 - 56.009 - 78.2=−104,759 (all you have to is to put them all together, and than make it 29.45 less, writing - in front of them)

(Explanation)

LAST ONE

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6 0
3 years ago
3 .912+s=5.313 evaluate
taurus [48]

Answer:

s= 1.401

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3 years ago
A road perpendicular to a highway leads to a farmhouse located d miles away. An automobile traveling on this highway passes thro
pshichka [43]

Answer:

\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}

Step-by-step explanation:

A road is perpendicular to a highway leading to a farmhouse d miles away.

An automobile passes through the point of intersection with a constant speed \frac{dx}{dt} = r mph

Let x be the distance of automobile from the point of intersection and distance between the automobile and farmhouse is 'h' miles.

Then by Pythagoras theorem,

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By taking derivative on both the sides of the equation,

(2h)\frac{dh}{dt}=(2x)\frac{dx}{dt}

(h)\frac{dh}{dt}=(x)\frac{dx}{dt}

(h)\frac{dh}{dt}=rx

\frac{dh}{dt}=\frac{rx}{h}

When automobile is 30 miles past the intersection,

For x = 30

\frac{dh}{dt}=\frac{30r}{h}

Since h=\sqrt{d^{2}+(30)^{2}}

Therefore,

\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+(30)^{2}}}

\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}

3 0
3 years ago
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