The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
<h3>What is the radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.?</h3>
Generally, the equation for side lengths AB is mathematically given as
Triangle ABC has side lengths
Where
- AB = 65,
- BC = 33,
- AC = 56.
Hence
r √ 2 · (89 √ 2/2 − r √ 2) = r(89 − 2r),
r = 89 − 65
r= 24.
In conclusion, The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
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We know, Volume of a Cone = πr² h/3
v = 3.14 * (6)² * 11.4/3
v = 3.14 * 36 * 3.8
v = 429.552
Now, for 1 m³, it costs = $20
So, for 429.552 m³, it will be: 20 * 429.552 = 8591
In short, Your Answer would be $8591
Hope this helps!
Answer: Parallel: y=-2/7x-2 1/7 Perpendicular: y=7/2x+13
Step-by-step explanation:
2x+7y=14
Subtract 2x from both sides.
7y=-2x+14
Divide both sides by 7 to isolate y.
y=-2/7x+2
Parallel:
Plug in x and y with same slope as the original.
-1=-2/7(-4)+b
Solve for b:
-1=8/7+b
-2 1/7=b
y=-2/7x-2 1/7
Perpendicular:
Plug in x and y with the negative inverse of the original slope.
-1=7/2(-4)+b
Solve for b.
-1=-28/2+b
-1=-14+b
13=b
y=7/2x+13
The quotient of two positive integers or two negative integers is positive. The quotient of a positive integer and a negative is negative. Hope you understand how to divide integers now.
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