All categories

3 years ago

NEED HELP HELP ME PLEASE

Mathematics

1 answer:

Sveta_85 [38]3 years ago

8 0

I cant understand the equation. Pic blurry

You might be interested in

How do I find the radius of a circle?

Rina8888 [55]

Figure out the radius then divide it by two. The diameter is one end of a circle to another.

6 0

3 years ago

Read 2 more answers

Which property justifies this question -5 x 12 = 12 x -5

cluponka [151]

Answer:

Commutative Property of Multiplication

Step-by-step explanation:

Commutative Property of Multiplication is the switching of the order first factor (multiplicand) and the second factor (multiplier), which does not change the product. For example, 4 × 5 = 5 × 4

-5 × 12 = -60

12 × -5 = -60

8 0

2 years ago

Help me I got 25 missing assignments

leva [86]

Answer:

think it's the last one

Step-by-step explanation:

sorry if i'm wrong

6 0

3 years ago

Quadrilateral OPQR is inscribed inside a circle as shown below. What is the measure of angle Q? You must show all work and calcu

viktelen [127]

Hello,

Angles y and 3y+8 are supplementaries since the quadrilater is inscribed

y+3y+8=180
==>4y=172
==>y=43 (°)

8 0

3 years ago

Past records indicate that the probability of online retail orders that turn out to be fraudulent is 0.08. Suppose that, on a gi

Sunny_sXe [5.5K]

Answer:

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

Step-by-step explanation:

We can model this with a binomial random variable, with sample size n=20 and probability of success p=0.08.

The probability of k online retail orders that turn out to be fraudulent in the sample is:

$P(x=k)=\dbinom{n}{k}p^k(1-p)^{n-k}=\dbinom{20}{k}\cdot0.08^k\cdot0.92^{20-k}$

We have to calculate the probability that 2 or more online retail orders that turn out to be fraudulent. This can be calculated as:

$P(x\geq2)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0)=\dbinom{20}{0}\cdot0.08^{0}\cdot0.92^{20}=1\cdot1\cdot0.189=0.189\\\\\\P(x=1)=\dbinom{20}{1}\cdot0.08^{1}\cdot0.92^{19}=20\cdot0.08\cdot0.205=0.328\\\\\\\\P(x\geq2)=1-[0.189+0.328]\\\\P(x\geq2)=1-0.517=0.483$

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

5 0

3 years ago