Ask question

Ask question

All categories

3 years ago

10

Which mixed number is equal to 8/3

1 answer:

pentagon [3]3 years ago

7 0

2 2/3 because 3 goes into 8 twice with a remainder of 2 therefore giving you 2 2/3 i hope this helps

You might be interested in

I’ll mark as brainliest help plsss

tankabanditka [31]

It would be exponential

4 0

3 years ago

What f(x)=5x^2+7x-3 degree

enot [183]

Answer:

Step-by-step explanation:

The degree of a polynomial is the highest exponent. Our highest exponent is a 2, so we have a second degree polynomial.

7 0

3 years ago

20 to 14 is the same as 8 to R solve for R

riadik2000 [5.3K]

Answer:

x=5.6

Step-by-step explanation:

Look at drawing seen above.

8 0

4 years ago

WILL MARK CORRECT ANSWER BRAINLIEST

vladimir1956 [14]

3y^-4/3 x 2 3/y
Write in exponential form with the base of y
= 3y^-4/3 x 2y^1/3
Calculate the product
= 6y^-1
Any expression raised to the power of equals its reciprocal
= 6 x 1/y
Calculate the product
= 6/y

8 0

3 years ago

What is the zero of the function

olga_2 [115]

Answer:

$x=6$ (or 6)

Step-by-step explanation:

<u>Set f(x)=0:</u>

$f(x)=\frac{x^2+x-42}{x^2+3x-28}$

$0=\frac{x^2+x-42}{x^2+3x-28}$

$0=x^2+x-42$

$0=(x+7)(x-6)$

$x=-7$ or $x=6$

<u>Now check both solutions:</u>

$f(-7)=\frac{(-7)^2+(-7)-42}{(-7)^2+3(-7)-28}$

$f(-7)=\frac{49-7-42}{49-21-28}$

$f(-7)=\frac{42-42}{28-28}$

$f(-7)=\frac{0}{0}$

Therefore, $x\neq-7$ because there is a hole at $(-7,0)$ . The denominator, in addition, can never be 0, so the function is undefined for $x=-7$ .

$f(6)=\frac{(6)^2+(6)-42}{(6)^2+3(6)-28}$

$f(6)=\frac{36+6-42}{36+18-28}$

$f(6)=\frac{42-42}{54-28}$

$f(6)=\frac{0}{24}$

$f(6)=0$

Since $f(6)=0$ , then $x=6$ is the only zero of the function.

4 0

3 years ago