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Answer:
The value of f(0)=1
Step-by-step explanation:
We are given that
![f(x)=k](https://tex.z-dn.net/?f=f%28x%29%3Dk)
![y=f(x)](https://tex.z-dn.net/?f=y%3Df%28x%29)
(6,1) and (8,1) lies on the graph of y=f(x)
We have to find the value of f(0).
![f(6)=1](https://tex.z-dn.net/?f=f%286%29%3D1)
![f(8)=1](https://tex.z-dn.net/?f=f%288%29%3D1)
![f(x)=k](https://tex.z-dn.net/?f=f%28x%29%3Dk)
By comparing ,we get
k=1
Therefore, ![y=f(x)=1](https://tex.z-dn.net/?f=y%3Df%28x%29%3D1)
Now, substitute x=0
![f(0)=1](https://tex.z-dn.net/?f=f%280%29%3D1)
Hence, the value of f(0)=1
Answer:
<h3>
A.</h3>
Step-by-step explanation:
if both increases the volume also increase as the same i.e.
twice length and twice radius = twice the volume of wax
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Use the distributive property to get... 2.4a - 0.48b + 8.4c