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4 years ago

Plz help ASAP!!!! WILL MARK YOU BRAINLIST IF YOUR ANSWER IS CORRECT!! Question # 7 last question

Mathematics

2 answers:

Korvikt [17]4 years ago

7 0

Answer:

the last one

Step-by-step explanation:

i took the test

oksano4ka [1.4K]4 years ago

6 0

<h3>Answer: Choice A</h3>

If you plug x = 3 into choice A, then you dont have any division by zero errors or square roots of negative values.

Choice B in contrast has x-9 = 3-9 = -6 under the square root, so this leads to an imaginary/complex result. Choice D is similar.

Choice C will have zero in the denominator after plugging in x = 3 since x^2-9 = 3^2-9 = 9-9 = 0.

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A. 110<br> B. 75<br> C. 55 <br> D. 125 <br> Please help asap

hjlf

The correct answer is 55 degrees as it is a property that if two same points have two angles one from the centre and other somewhere on the edge then it gets half.

3 0

4 years ago

-4x - 6 = -5y + 9 y=

xxMikexx [17]

Answer:

y =4/5x + 3

Step-by-step explanation:

−4x−6=−5y+9

Step 1: Flip the equation.

−5y+9=−4x−6

Step 2: Add -9 to both sides.

−5y+9+−9=−4x−6+−9

−5y=−4x−15

Step 3: Divide both sides by -5.

−5y/−5

−4x−15/−5

4/5x+3

Answer:

4/5x+3

5 0

4 years ago

Read 2 more answers

21.What is the value of their expression below?<br><br> 18-3(1 + 5)

erica [24]

Step-by-step explanation:

3 is being multiplied by the numbers in the bracket so

18-(3x1+3x5)

18-(3+15)

18-(18)

answer is 0

3 0

3 years ago

Calculate the integral s f · ds, where s is the entire surface of the solid half ball x2 + y2 + z2 ≤ 1, z ≥ 0, and f = (x + 3y5)

SSSSS [86.1K]

The divergence theorem applies since $\mathcal S$ is a closed surface. We have

$\displaystyle\iint_{\mathcal S}\mathbf f(x,y,z)\cdot\mathrm d\mathbf S=\iiint_{\mathcal V}\nabla\times\mathbf f(x,y,z)\,\mathrm dV$

where $\mathcal V$ is the space enclosed by the surface $\mathcal S$ . The divergence of the given vector field is

$\nabla\times\mathbf f(x,y,z)=\dfrac{\partial(x+3y^5)}{\partial x}+\dfrac{\partial(y+10xz)}{\partial y}+\dfrac{\partial(z-xy)}{\partial z}=1+1+1=3$

So we can write the volume integral (in spherical coordinates) as

$\displaystyle3\iiint_{\mathcal V}\,\mathrm dV=3\int_{\varphi=0}^{\varphi=\pi/2}\int_{\theta=0}^{\theta=2\pi}\int_{\rho=0}^{\rho=1}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=\frac{4\pi}3$

6 0

3 years ago

What is the volume (in cubic units) of a cone with a radius of 6

kykrilka [37]

Evaluate the volume with the given measurements.

Answer: 376.8 m^3

3 0

3 years ago