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3 years ago

-4²+6·-4+9 please!!! answer

Mathematics

1 answer:

kumpel [21]3 years ago

6 0

It’s: -31
when you are simplify this expression you get -31

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3 years ago

4,756 rounded to the nearest thousand is

Shalnov [3]

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3 years ago

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I need help with this i can’t graph

zaharov [31]

Answer:

(-2,-5), (0,-4), (3,5) (1,1)

Solution:

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3 years ago

Question 15 please and i will mark the brainliest!!! And thank you to whoever answers

Oksanka [162]

<h3>Answer: C) 12</h3>

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3 years ago

What are the endpoint coordinates for the midsegment of △BCD that is parallel to BC?

natulia [17]

Answer:

<em>The endpoint coordinates for the mid-segment are: $(-2,-1)$ and $(1,0)$ </em>

Step-by-step explanation:

According to the given diagram, the coordinates of the vertices of $\triangle BCD$ are: $B(-3,1), C(3,3)$ and $D(-1,-3)$

Now, the endpoints of the mid-segment of $\triangle BCD$ which is parallel to $BC$ will be the mid-points of sides $BD$ and $CD$ .

<u>Formula for the coordinate of mid-point</u> : $(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})$ , where $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ are two endpoints.

So, the mid-point of $BD$ will be: $(\frac{-3-1}{2},\frac{1-3}{2})=(\frac{-4}{2},\frac{-2}{2})=(-2,-1)$

and the mid-point of $CD$ will be: $(\frac{3-1}{2},\frac{3-3}{2})=(\frac{2}{2},\frac{0}{2})=(1,0)$

Thus, the endpoint coordinates for the mid-segment of $\triangle BCD$ that is parallel to $BC$ are $(-2,-1)$ and $(1,0)$

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3 years ago

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