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2 years ago

The set of x valúes of a function this is another name of range

Mathematics

1 answer:

marin [14]2 years ago

8 0

Answer:

False?

Step-by-step explanation:

We can't tell what the question is here, but it looks like you want to know about the definition of domain and range.

The set of x-values is the <em>domain</em>.

The set of y-values is the <em>range</em>.

"range" is <u>not</u> another name for the set of x-values.

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Can someone help me figure out the answer to:<br><br>3 5/8 + 4 2/3?<br><br>(please explain working?)

ivanzaharov [21]

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Ex) 3*8 = 24 + 5 = 29/8
Then you would add both of the improper fractions

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3 years ago

Perform the indicated operations.Express the answer in its lowest terms.

Marat540 [252]

Answer:

BlueSky06

2, 4, 5, 5, 6, 6, 7, 7, 7, 8, 8, 9, 9, 10

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Using the given information, give the vertex form equation of each parabola.

Amanda [17]

Answer:

The equation of parabola is given by : $(x-4) = \frac{-1}{3}(y+3)^{2}$

Step-by-step explanation:

Given that vertex and focus of parabola are

Vertex: (4,-3)

Focus:( $\frac{47}{12}$ ,-3)

The general equation of parabola is given by.

$(x-h)^{2} = 4p(y-k)$ , When x-componet of focus and Vertex is same

$(x-h) = 4p(y-k)^{2}$ , When y-componet of focus and Vertex is same

where Vertex: (h,k)

and p is distance between vertex and focus

The distance between two points is given by :

L= $\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}$

For value of p:

p= $\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}$

p= $\sqrt{(4-\frac{47}{12})^{2}+((-3)-(-3))^{2}}$

p= $\sqrt{(\frac{1}{12})^{2}}$

p= $\frac{1}{12}$ and p= $\frac{-1}{12}$

Since, Focus is left side of the vertex,

p= $\frac{-1}{12}$ is required value

Replacing value in general equation of parabola,

Vertex: (h,k)=(4,-3)

p= $\frac{-1}{12}$

$(x-h) = 4p(y-k)^{2}$

$(x-4) = 4(\frac{-1}{12})(y+3)^{2}$

$(x-4) = \frac{-1}{3}(y+3)^{2}$

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3 years ago

Corrine wrote temperatures in degrees Celsius and the equivalent temperatures in degrees Fahrenheit.

Gekata [30.6K]

Draw a graph of the temperatures; if the points form a straight line, then the temperatures vary directly , Option B is the correct answer.

<h3>What is Direct Variation ?</h3>

When a quantity of one variable is increased and the value of the other also increases then they are said to be in direct variation.

For the data to be in direct variation

Draw a graph of the temperatures; if the points form a straight line, then the temperatures vary directly.

The points in any linear equation can only fluctuate directly, therefore all points will lie on the same line.

Option B is the correct answer.

To know more about Direct Variation

brainly.com/question/14254277

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2 years ago

in the following diagrams ABD=y,DBC=x,EFH=y, EFG=x and PQS=SQR=x.write the following in terms of x and y ABC

Leokris [45]

Angles are the space between intersecting lines, and they are measured in degrees or radians

The measure of angle ABC is y + x

<h3>How to determine angle ABC</h3>

The given parameters are:

ABD=y,

DBC=x,

EFH=y,

EFG=x

PQS = SQR = x

To determine the measure of angle ABC, we make use of angle ABD and angle DBC

Note that angle ABD and angle DBC have common vertices at points B and D

So, we have:

ABC = ABD + DBC

Substitute known values

ABC = y + x

Hence, the measure of angle ABC is y + x