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DanielleElmas [232]
3 years ago
14

The set of x valúes of a function this is another name of range

Mathematics
1 answer:
marin [14]3 years ago
8 0

Answer:

  False?

Step-by-step explanation:

We can't tell what the question is here, but it looks like you want to know about the definition of domain and range.

The set of x-values is the <em>domain</em>.

The set of y-values is the <em>range</em>.

__

"range" is <u>not</u> another name for the set of x-values.

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1/4 divided by 2/6 in simplest form
Nuetrik [128]

Answer:

1/4*6/2=6/8

3/4

Step-by-step explanation:

3 0
1 year ago
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I dont understand
crimeas [40]
To determine the inverse of a function, we first write the parent function in terms of y. So, in this part the x would be isolated to one side of the equation. Then, with the new form of the parent function, we switch the x into y and y to x. The new function would be the inverse function. For the given function, we do as follows:

<span> y=-4/x + 1 
y - 1 = -4/x
x ( y - 1 ) = -4
x = -4 / (y -1)

Replacing x into y and y into x,

</span>y = -4 / (x -1)

<span>Therefore, the inverse is y=-a/x-b where a = 4 and b = 1.</span>
6 0
3 years ago
The inverse of a function is a function?
Harlamova29_29 [7]

yes because you do the opposite so it would not be a function

5 0
3 years ago
Avani wrote the linear equation y = 5 x + 4. Then, she wrote the equation of the line that is perpendicular to y = 5 x + 4 and t
Margarita [4]

Avani wrote the linear equation y = 5x + 4. Then, she wrote the equation of the line that is perpendicular to y = 5x+ 4 and that passes through (15,–2). If her new equation is in the form  y-\frac{1}{5}x+b, what is the value of b?

\bf y=mx+b

  • m is the slope
  • b is the y-intercept

The equation of a line that is perpendicular to another line always has the opposite reciprocal slope. In the original equation, the slope is 5. The opposite of 5, which refers to the sign, is -5. The reciprocal of -5 is -1/5. That means the slope of the new line is -1/5.

The perpendicular line:

  • Has a slope of -\frac{1}{5}
  • Passes through the point (15, -2)

To find the equation of a line that passes through a specific point, you need to use slope-intercept form.

\bf y-y_{1} =m(x-x_{1})

  • y₁ is the y-value of the point
  • m is the slope
  • x₁ is the x-value of the point

y₁ is -2, m is -1/5,  and x₁ is 15.

Substitute the known values into the equation:

y-(-2)=-\frac{1}{5}(x-15) \rightarrow y+2= -\frac{1}{5}(x-15)

Open the parentheses and distribute:

-\frac{1}{5}(x-15) \rightarrow -\frac{1}{5} \cdot x\ +  -\frac{1}{5} \cdot -15 \rightarrow -\frac{1}{5}x +3

The new equation will be:

y+2=-\frac{1}{5}x+3

Lastly, you need to move the positive 2 to the other side to keep it in y = mx + b form.

y+2-2=-\frac{1}{5}x+3-2 \rightarrow y=-\frac{1}{5}x+1

The equation of the perpendicular line is:

\bf y=-\frac{1}{5}x+1

The value of b is 1.

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3 years ago
Hurry fasttt fastttt
I am Lyosha [343]
The first option I believe thank me plz
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