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dybincka [34]
3 years ago
5

Evaluate 3 + jk + k3 when j = 2 and k = 6.

Mathematics
2 answers:
torisob [31]3 years ago
8 0

Answer:

<h2>231</h2>

Step-by-step explanation:

3 + jk +k^3\\ j = 2 \\ k = 6

Substitute values into the given equation

3 + 2(6)+(6)^3 \\ 3 + 12+216 \\  = 231

PIT_PIT [208]3 years ago
3 0

Answer:

231

Step-by-step explanation:

3+jk+k^{3} \\\\j=2\\\\k=6\\\\3+jk+k^3\\\\=3+(2)(6)+(6)^3\\\\=3+12+216\\\\=231

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A mountain climber camped at an elevation of 18,492 feet. The following day the climber descended 2,516 feet to another campsite
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Answer:

18492-2516

Elevation: 15976

Step-by-step explanation:

Since the climber descended 2516 feet, we can write 18492-2516.

3 0
3 years ago
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Mari packs the same number of oranges in each bag. How many oranges does Mari need to pack 9 bags? How can you determine the num
GuDViN [60]

Answer:

Mari needs 27 and 39 oranges for 9 and 13 bags respectively.

Step-by-step explanation:

Consider the below figure attached with this question.

From the below table it is clear the she need 9 oranges for 3 bags.

Number of oranges in each bag = 9/3 = 3 oranges

She packs 3 oranges in each bag.

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For 13 bags, the number of oranges = 13×3 = 39 oranges.

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3 0
3 years ago
Help please, question attached
Alexxandr [17]

Answer:

C. x = 8

Step-by-step explanation:

We know that x · x · x is equal to 512. We know it cannot be negative because then the 512 would be negative. -2 x -2 x -2 is -8. -2 x -2 is 4. We know it cannot be B x = -6 or D. x = -8.

Let's multiply 6 x 6 x 6.

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Let's multiply 8 x 8 x 8.

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The answer would be C. x = 8.

I hope that this helps! :)

4 0
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6 0
3 years ago
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