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3 years ago

Evaluate 3 + jk + k3 when j = 2 and k = 6.

Mathematics

2 answers:

torisob [31]3 years ago

8 0

Answer:

Step-by-step explanation:

$3 + jk +k^3\\ j = 2 \\ k = 6$

Substitute values into the given equation

$3 + 2(6)+(6)^3 \\ 3 + 12+216 \\ = 231$

PIT_PIT [208]3 years ago

3 0

Answer:

231

Step-by-step explanation:

$3+jk+k^{3} \\\\j=2\\\\k=6\\\\3+jk+k^3\\\\=3+(2)(6)+(6)^3\\\\=3+12+216\\\\=231$

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Is this equation true? 1.2(2x-5)=2/5(2x-15)+1.6x

kobusy [5.1K]

Answer:

no, there is an infatuate amount of solutions

Step-by-step explanation:

1.2(2x-5)=2/5(2x-15)+1.6x

2.4x -6 = .8x -6 +1.6

2.4 -6 = 2.4-6

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7 0

3 years ago

Fraction simple 25/100

steposvetlana [31]

Answer:1/4

Step-by-step explanation:

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2 years ago

In a stack of boards at a lumber yard, the 20th board counting from the top of the stack is immediately below the 16th board cou

motikmotik

Answer:

D.34

Step-by-step explanation:

Let's the A be the 20th board counting from the top of the stack, and B be the 16th board counting from the bottom of the stack. If A is immediately below B, this means B is the 19th board counting from the top of the stack, and also there are 18 other boards that are above B. So the total number of board in the stack would be

16 + 18 = 34

D is the correct answer

7 0

3 years ago

Pls help this is due tomorrow-

Vladimir79 [104]

Answer:

Step-by-step explanation:

1- $1 \frac{34}{55}$

2- $1 \frac{1}{18}$

3- $\frac{67}{72}$

4- $\frac{19}{24}$

5- $1 \frac{7}{33}$

6- $\frac{19}{20}$

7- $1 \frac{1}{3}$

8- $\frac{5}{7}$

9- $\frac{5}{6}$

10- $\frac{7}{12}$

4 0

2 years ago

Consider the equation and its solution.

expeople1 [14]

Answer:

<h2>D. division property of equality</h2>

Step-by-step explanation:

$8(x-2)=64\qquad\text{distributive property}\\8x-(8)(2)=64\\8x-16=64\qquad\text{add 16 to both sides}\\8x-16+16=64+16\qquad\text{addition property of equality}\\8x=80\qquad\text{divide both sides by 8}\\\dfrac{8x}{8}=\dfrac{80}{8}\qquad\text{division property of equality}\\x=10$

7 0

2 years ago