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dybincka [34]
3 years ago
5

Evaluate 3 + jk + k3 when j = 2 and k = 6.

Mathematics
2 answers:
torisob [31]3 years ago
8 0

Answer:

<h2>231</h2>

Step-by-step explanation:

3 + jk +k^3\\ j = 2 \\ k = 6

Substitute values into the given equation

3 + 2(6)+(6)^3 \\ 3 + 12+216 \\  = 231

PIT_PIT [208]3 years ago
3 0

Answer:

231

Step-by-step explanation:

3+jk+k^{3} \\\\j=2\\\\k=6\\\\3+jk+k^3\\\\=3+(2)(6)+(6)^3\\\\=3+12+216\\\\=231

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1 year ago
13 is the same as 1÷3. What is the exact quotient in decimal form of 1÷3?
meriva

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4 0
4 years ago
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Answer:

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