Let <span>sin(90° - )------------------------ > sin (90-x)
</span>sin(a - b<span>) = sin a*cos b - cos a*sin b
</span><span>so
</span>sin(90 - x) = sin 90*cos x - cos 90 * sin x
sin(90 - x) = 1*cos x - 0* sin x-------- > cos x
the answer is the option <span>D. cos()</span><span>
</span>
Your rate of change is y2-y1/x2-x1, so it is 12-6/1-0 which simplifies to 6/1 or 6.
Answer:
The center is (0,0).
Explanation:
To find the center of a circle, you have to look at the x^2 and the y^2. Because there are no numbers with them in the equation, the center of the circle does not move. If the equation has been like (x-5)^2 + (y-2)^2=16, then the center of the circle would be at (5,2)
Using 5, you can reduce 10/45
so the answer is 2/9